Hi,
I am working on an article for the Python Software Foundation's blog,
http://pyfound.blogspot.com/, about the various Python projects that
were worked on during this year's Google Summer of Code program. They
want me to write up something about what projects were worked on and
what the results
Hi Mike!
On Thu, Sep 16, 2010 at 6:42 AM, Mike Driscoll wrote:
> Hi,
>
> I am working on an article for the Python Software Foundation's blog,
> http://pyfound.blogspot.com/, about the various Python projects that
> were worked on during this year's Google Summer of Code program. They
> want me t
I will try to finish my writeup today or tomorrow :).
Aaron Meurer
Sent from my iPod touch.
On Sep 16, 2010, at 11:34 AM, Ondrej Certik wrote:
Hi Mike!
On Thu, Sep 16, 2010 at 6:42 AM, Mike Driscoll
wrote:
Hi,
I am working on an article for the Python Software Foundation's blog,
http:/
Hi,
today I have discovered (by accident), that you can very easily
generate all the sin/cos multiple angle formulas, like:
sin(2*x) = 2*cos(x)*sin(x)
sin(3*x) = -(1 - 4*cos(x)**2)*sin(x)
sin(4*x) = (-4*cos(x) + 8*cos(x)**3)*sin(x)
cos(2*x) = -1 + 2*cos(x)**2
cos(3*x) = -3*cos(x) + 4*cos(x)**3
co
Hi,
On Thu, Sep 16, 2010 at 04:30:41PM -0700, Ondrej Certik wrote:
> Hi,
>
> today I have discovered (by accident), that you can very easily
> generate all the sin/cos multiple angle formulas, like:
>
> sin(2*x) = 2*cos(x)*sin(x)
> sin(3*x) = -(1 - 4*cos(x)**2)*sin(x)
> sin(4*x) = (-4*cos(x) + 8
On Thu, Sep 16, 2010 at 4:38 PM, Mateusz Paprocki wrote:
> Hi,
>
> On Thu, Sep 16, 2010 at 04:30:41PM -0700, Ondrej Certik wrote:
>> Hi,
>>
>> today I have discovered (by accident), that you can very easily
>> generate all the sin/cos multiple angle formulas, like:
>>
>> sin(2*x) = 2*cos(x)*sin(x)
Hi,
On Thu, Sep 16, 2010 at 04:51:37PM -0700, Ondrej Certik wrote:
> On Thu, Sep 16, 2010 at 4:38 PM, Mateusz Paprocki wrote:
> > Hi,
> >
> > On Thu, Sep 16, 2010 at 04:30:41PM -0700, Ondrej Certik wrote:
> >> Hi,
> >>
> >> today I have discovered (by accident), that you can very easily
> >> gene
I get 8.94, 0.01, 0.00 on the first run and 1.31, 0.01, 0.00 on subsequent runs
(cache enabled).
But more importantly, I get this:
In [69]: a = sin(40*x).expand(trig=True)
In [70]: b = chebyshevt(40, cos(x))
In [71]: c = chebyshevt_poly(40, cos(x))
In [72]: a == b
Out[72]: False
In [73]: a =
I think you want the collect() function and the .as_independent
method. The easiest way to manipulate Equalities is to first convert
them into regular expressions. Then, you would call collect on the
expression using x**2. collect collects all powers of the argument
by default, but you can
Hi again.
On Sep 16, 2010, at 9:51 PM, Nicholas Kinar wrote:
>
>>> I think you want the collect() function and the .as_independent method.
>>> The easiest way to manipulate Equalities is to first convert them into
>>> regular expressions. Then, you would call collect on the expression using
If the second one had given set([M(i, j) ,M(1 + i, j)]), then you could have
had something to work with (Chris or Oyvind, do you know why it does this?).
Of course, the way I gave again above will still work, if you know what the M's
are in the expression:
In [104]: expr = expr.lhs - expr.rh
.atoms() is the standard way to get all the similar kinds of objects in an
expression, so it is a shame that it isn't working in this case. I opened
issue (2058) for this (see
http://code.google.com/p/sympy/issues/detail?id=2058).
Feel free to lend your help in fixing it. Something just as
On 10-09-16 10:33 PM, Aaron S. Meurer wrote:
.atoms() is the standard way to get all the similar kinds of objects in an
expression, so it is a shame that it isn't working in this case. I opened
issue (2058) for this (see
http://code.google.com/p/sympy/issues/detail?id=2058).
Feel free to le
On Thu, Sep 16, 2010 at 5:32 PM, Aaron S. Meurer wrote:
> I get 8.94, 0.01, 0.00 on the first run and 1.31, 0.01, 0.00 on subsequent
> runs (cache enabled).
>
> But more importantly, I get this:
>
> In [69]: a = sin(40*x).expand(trig=True)
>
> In [70]: b = chebyshevt(40, cos(x))
>
> In [71]: c =
14 matches
Mail list logo
