This is the code along with documentation
from sympy import diff, integrate, sympify, expand, Symbol
x=Symbol('x')
def Delta(expr, d = 1):
"""Takes as input function expression and returns the diffrence
between final value(function's expression incremented to 1) and
initial value (function
It's hard to tell without seeing the code. What you wrote should work.
Aaron Meurer
On Jul 7, 2012, at 5:44 AM, Saurabh Jha wrote:
> Hi,
>
>I implemented a Delta() function as a part of my project of
> implementation of Kauers' algorithm
>
>It takes as input function expression and retu
Once https://github.com/sympy/sympy/pull/1258 is fixed and merged,
trigsimp() will be able to do it.
Aaron Meurer
On Jul 7, 2012, at 4:41 PM, Chris Smith wrote:
> On Sat, Jul 7, 2012 at 10:48 AM, pallab wrote:
>> How to get that
>>
>> sin(4)-2*cos(2)*sin(2)
>>
>> is zero?
>
>
eq
> sin(4)
On Sat, Jul 7, 2012 at 10:48 AM, pallab wrote:
> How to get that
>
> sin(4)-2*cos(2)*sin(2)
>
> is zero?
>>> eq
sin(4) - 2*sin(2)*cos(2)
>>> simplify(eq.rewrite(exp))
0
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How to get that
sin(4)-2*cos(2)*sin(2)
is zero?
simplify, trigsimp, expand(trig=true) nothing works.
Pallab
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It does work. Sorry that I made a mistake.
On Saturday, July 7, 2012 6:30:26 AM UTC-4, rl wrote:
>
> A first start:
>
> http://github.com/sympy/sympy/pull/1408
>
>
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Hi,
I implemented a Delta() function as a part of my project of
implementation of Kauers' algorithm
It takes as input function expression and returns the difference
between final value(function's expression incremented to 1) and
initial value (function's expression)
.
I saved the cha
A first start:
http://github.com/sympy/sympy/pull/1408
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Hi,
There are a couple of things to say here. First I think you have
confused when you give boundaries via x or via z. After substitution,
the integrand becomes sqrt(z)/sqrt(1-z**2), so let's discuss this. Then
we have:
In [26]: i = Integral(sqrt(z)/sqrt(1-z**2), (z, 0.3, 0.4))
In [29]: i.do
Hey all, I have a Python module that does symbolic Boolean algebra at:
https://github.com/cjdrake/pyeda
It's just a hobby project for me to hack on EDA algorithms, and so far I
have only gotten to expression representations. It might be interesting to
sympy crowd b/c I chose not to automaticall
Am 07.07.2012 01:18, schrieb Aaron Meurer:
According to http://en.wikipedia.org/wiki/Elliptic_integral, every
elliptic integral can be reduced to an expression containing only the
three Legendre canonical forms. So I wonder if that is algorithmic.
The article says you need to find the "appropr
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