My previous message can be ignored -- as Aaron pointed out (thank you!)
this has been fixed, I was not using a recent-enough release. Sorry for
the noise.
Python 3.9.2 (default, Mar 31 2021, 11:25:52)
[Clang 10.0.1 (clang-1001.0.46.4)] on darwin
Type "help", "copyright", "credits" or "license"
What is described above has worked well for me. But there is a further
simplification step that I need help with.
I have some long expressions containing terms contain terms which look like
this example:
sqrt(4*a**2 + 1)*sqrt(1/(4*a**6 - 15*a**4 + 12*a**2 + 4))
How can I instruct sympy to combi
Here is one solution that seems to work. To simplify Z I use
Z.replace(Abs, MyAbs) with
def MyAbs(x):
x1=symbols('x1',real=True,positive=True)
x1 = x.evalf(subs={a:0.573})
if x1 < 0.0:
return S(-1)*x
else:
return x
Is this a reasonable way to go, or are there gotc
Could anyone suggest a solution for this? I can make a list of
substitutions by hand (as below) and pass that to the .subs() method, but
surely there is a better way.
s_list={
Abs(a - 1) : S(1) - a,
Abs(a - 2) : S(2) - a,
Abs(2*a - 3) : S(3) - S(2)*a,
Abs(a
I am a sympy beginner, and fairly new to python, so I suspect that my
question has a simple answer, but have not been able to figure it out
myself.
I have sympy expressions containing the built-in Abs function. The
arguments of Abs() are polynomials in a=symbol('a',
real=True,positive=True) .
