Hello,
I tried to find the roots of : 2*sqrt(x)*sqrt(x**3 - x**2 + 1) + 2*x**3 -
x**2 + x*sqrt(x**3 - x**2 + 1) + 2*x**1.5 + 2*x**2.5*sqrt(x**3 - x**2 + 1)
- 3*x**2.5 - 4*x**3.5*sqrt(x**3 - x**2 + 1) - 2*x**3.5 + 5*x**4.5 -
3*x**5.5 - 1 = 0.
x = symbols('x', real=True)
f = Lambda(x,
Meurer
On Tue, May 19, 2015 at 6:29 AM, Arnaud Usciati rai...@gmail.com
javascript: wrote:
Hello,
I tried to find the roots of : 2*sqrt(x)*sqrt(x**3 - x**2 + 1) + 2*x**3
-
x**2 + x*sqrt(x**3 - x**2 + 1) + 2*x**1.5 + 2*x**2.5*sqrt(x**3 - x**2 +
1) -
3*x**2.5 - 4*x**3.5*sqrt(x**3
Right,
I have sympy-0.7.6.win32.
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Hello,
I found two issues with factor().
If x = symbols('x', real=True)
f = Lambda(x, (-2*x + Abs(x))*Abs(x**2 - 1))
g = Lambda(x, diff(f(x), x))
Input : g(x)
Ouput : 2*x*(-2*x + Abs(x))*sign(x**2 - 1) + (sign(x) - 2)*Abs(x**2 - 1)
Input : factor(g(x))
Ouput : -4*x**2*sign(x**2 - 1) +
Hello,
I found 2 issues with limit().
x = symbols(x, real=True)
f = Lambda(x, (x+exp(x))/(x-1))
Input : limit(f(x), x, -oo, '+')
Output : 0 -- Wrong
Input : limit(expand(f(x)), x, -oo, '+')
Output : 1 -- Correct
g = Lambda(x, (ln(x)-1)**(1-sqrt(x)))
Input : limit(g(x), x, E, '+')
Ouput : 0 --
Hello everybody,
I tried values with acosh function and I found an issue.
Suppose x = symbols('x', real=True) and f = lambda x: acosh(-x).
For instance :
Input : f(1)
Output : I*pi
-- That's OK
Input : f(-1)
Output : 0
-- That's OK
But f(x) returns -acosh(x) instead of acosh(-x) ! It's
Hello,
If x = symbols('x', real=True).
I found wrong results for limits with sign() function.
limit(sign(x), x, 0, '+') = 1, and limit(sign(x), x, 0, '-') = -1 --- OK
But :
- limit(sign(ln(x)), x, 1, '+') = 1 (OK) but limit(sign(ln(x)), x, 1, '-')
= 0 instead of -1 ;
- limit(sign(sin(x)), x,
Hello,
I propose to add the following hyperbolic functions in order to complete
sympy. If f is a function :
sech(f) = 1/cosh(f)
csch(f) = 1/sinh(f)
asech(f) = acosh(1/f)
acsch(f) = asinh(1/f)
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To
février 2015 12:27:23 UTC+1, Christophe Bal a écrit :
Hello.
Maybe, it could be useful to have a abssimplify method that will try to
simplify abs expressions.
Christophe BAL
Le 11 févr. 2015 11:54, Arnaud Usciati rai...@gmail.com javascript:
a écrit :
Hi,
I found another error
, Douglas Lohmann dloh...@gmail.com
javascript: wrote:
In my test it's not a bug. You can explain better?
In [9]: limit(abs(log(x)), x, 0, '+')
Out[9]: oo
It was already reported the bug to the bug list?
Em sábado, 31 de janeiro de 2015 13:33:40 UTC-2, Arnaud Usciati
30, 2015 at 7:27 AM, Arnaud Usciati rai...@gmail.com
javascript: wrote:
Hello,
I try to find solutions for : 8.99*x*(-x + 1)**1.9 + 3.1*(-x + 1)**2.1 -
3.1*(-x + 1)**2.9 == 0
I use solve(8.99*x*(-x + 1)**1.9 + 3.1*(-x + 1)**2.1 - 3.1*(-x +
1)**2.9, x) but it runs endless
Any ideas
Hello,
I try to find solutions for : 8.99*x*(-x + 1)**1.9 + 3.1*(-x + 1)**2.1 -
3.1*(-x + 1)**2.9 == 0
I use solve(8.99*x*(-x + 1)**1.9 + 3.1*(-x + 1)**2.1 - 3.1*(-x +
1)**2.9, x) but it runs endless
Any ideas to fix it ?
PS : sorry for my english, i'm french :)
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Hello,
limit(abs(log(x)), x, 0, '+') should return +oo, but it
returns -oo*sign(log(_w)) !!!
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