Hi everyone,
I am having trouble combining mpmath's findroot function with sympy.
Here is a short example of what I am trying to accomplish:
import sympy
import mpmath
mpmath.mp.dps = 45
x = sympy.var('x')
p = (5.0/2.0*x**3 - 3.0/2.0*x).as_poly()
print 'subs: ', mpmath.findroot(lambda xi: p.s
774596669241483377035853079956479922166584341
>
> In [38]: print 'exact: ', mpmath.sqrt(mpmath.mpf('3.0')/mpmath.mpf('5.0'))
> exact: 0.774596669241483377035853079956479922166584341
>
> In [39]: print 'lambda:', mpmath.findroot(lambda x: 5.0*x**3/2.0 - 3.0*x/2.0,
&g
:
> Well, it still fails there with the subs. Like I said, it's a bug. Can you
> open an issue for it?
>
> Aaron Meurer
>
> On May 26, 2011, at 9:09 PM, Matthew Emmett wrote:
>
> > Thanks for the quick reply Aaron. I will get the latest git version
> > an
Hi everyone,
I have some sympy code that generates Fortran code, and was wondering
if there a good way of simplifying the sympy expressions in order to
minimize the number of floating point operations that are required to
evaluate them numerically. Any suggestions?
Thanks,
Matt
--
You received
choose whether
> or not to apply each of them.
>
> If you haven't already I recommend asking a non-sympy-specific version of
> this question on scicomp.stackexchange.com
>
> On Thu, Jul 26, 2012 at 5:43 PM, Matthew Emmett wrote:
>>
>> Hi everyone,
>>
>> I
