rrors and the analytic and numerical results now
> agree (see attached) -
> On 2/10/23 11:32 AM, 'Tom van Woudenberg' via sympy wrote:
>
> This is the result in Python (same as in Maple): [image: downloaden
> (5).png]
>
> Op vrijdag 10 februari 2023 om 17:31:50 UTC+
This is the result in Python (same as in Maple): [image: downloaden (5).png]
Op vrijdag 10 februari 2023 om 17:31:50 UTC+1 schreef Tom van Woudenberg:
> Hi Brombo,
>
> Thank you for the update. It seems my previous posts didn't show up.
> Anyway, you result doesn't match t
01:08:56 UTC+1 schreef brombo:
> Attached are latest results (I had calculated the roots of the quadratic
> wrong) and a plot -
> On 2/8/23 4:24 AM, 'Tom van Woudenberg' via sympy wrote:
>
> Hi Brombo,
>
> Thank you for the extensive working-out. I really appreciate tha
Thank you brombo, I'll take a closer look at the file you send me!
Op maandag 6 februari 2023 om 22:29:25 UTC+1 schreef brombo:
> I cleaned things up here is what the notebook looks like (see attached
> html) -
>
>
> On 2/6/23 10:36 AM, 'Tom van Woudenberg'
3521.jpg]
Kind regards,
Tom van Woudenberg
Delft University of Technology
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T
I opened two issues: https://github.com/sympy/sympy/issues/24546 and
https://github.com/sympy/sympy/issues/24547
Op woensdag 18 januari 2023 om 12:47:05 UTC+1 schreef Oscar:
> On Wed, 18 Jan 2023 at 08:33, 'Tom van Woudenberg' via sympy
> wrote:
> >
> > Disabling
>
>>> .
>>>
>>> I recall Aaron Meurer mentioned that it would be nice to have a simpler
>>> way of setting that flag.
>>>
>>> Jeremy Monat
>>>
>>> On Tue, Jan 17, 2023 at 1:17 PM Oscar Benjamin
>>> wrote:
&
2*x**2/2 - Q*(x**4/24 - (a**4/24 - a**3*x/6 +
a**2*x**2/4 - a*x**3/6 + x**4/24)*Heaviside(-a + x)) - 35*(-a*x**2/2 +
a*x*(a + b) - a*(a + b)**2/2 - b*x**2/2 + b*x*(a + b) - b*(a + b)**2/2 +
x**3/6 - x*(a + b)**2/2 + (a + b)**3/3)*Heaviside(-a - b + x))/EI*
Would it be possible to implement a m
You're correct, I was running SymPy version 1.10.1. Thank you!
Op dinsdag 17 januari 2023 om 12:37:49 UTC+1 schreef Oscar:
> On Tue, 17 Jan 2023 at 11:31, Oscar Benjamin
> wrote:
> >
> > On Tue, 17 Jan 2023 at 10:39, 'Tom van Woudenberg' via sympy
Hi there,
I'm trying to symbolically evaluate an integral with SymPy:
*import sympy as spq, L, H = sp.symbols('q L H',positive=True,real=True)x =
sp.symbols('x',real=True)Lexact = sp.integrate(sp.sqrt((L*q/(2*H) -
q*x/H)**2 + 1),(x,0,L))print(Lexact)*
The result is:
*Integral(sqrt(4*H**2 +
Aaron Meurer
>
> On Thu, Jan 12, 2023 at 12:58 PM Tom van Woudenberg <
> tom.van.w...@gmail.com> wrote:
>
>> Hi there,
>>
>> I'm Tom van Woudenberg, lecturer at Delft University of Technology and
>> I'm new to this group. I've got the foll
Hi there,
I'm Tom van Woudenberg, lecturer at Delft University of Technology and I'm
new to this group. I've got the following problem when trying to solve an
ODE with a duhamel integral:
import sympy as sp
omega_n, F_0, m, Omega, zeta = sp.symbols('omega_n, F_0, m, Ome
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