Thank you. It works.
On Monday, August 10, 2020 at 11:04:38 PM UTC+3, Aaron Meurer wrote:
>
> I'm not sure if you can get that with nsimplify(). I tried playing
> with the tolerance and rational_conversion arguments, but it either
> tries to be smart and reconstruct the original fraction, or it
I'm not sure if you can get that with nsimplify(). I tried playing
with the tolerance and rational_conversion arguments, but it either
tries to be smart and reconstruct the original fraction, or it gives
the exact base-2 fraction represented by the float
(4793116746272885/1125899906842624).
If I
nsimplify((Integer(149)/25).evalf()) outputs 149.25, as expected
nsimplify((Integer(149)/35).evalf()) outputs 149/35, which is not expected
as it is repeating decimal.
How to make it perform approximation to given precision:
4257142857142857/10**15 ?
--
You received this message because you
