In [80]: Integer(1)
Out[80]: 1
In [81]: _.args
Out[81]: ()
Is this normal? I expected type(expr)(*expr.args) == expr to be always true.
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Aaron Meurer
On Sun, Mar 11, 2012 at 1:03 PM, krastanov.ste...@gmail.com
wrote:
> In [80]: Integer(1)
> Out[80]: 1
>
> In [81]: _.args
> Out[81]: ()
>
> Is this normal? I expected type(expr)(*expr.args) == expr to be always true.
>
> --
>
