On Thu, Jun 19, 2008 at 1:21 PM, tom [EMAIL PROTECTED] wrote:
I was just trying out sympy to try and make a few bits of hand-algebra
easier, and avoid mistakes, but am having some trouble.
I'm trying to factor out one variable, so tried (having set up a and b
as symbols):
factor(a*b+b, b)
On Thu, Jun 19, 2008 at 1:34 PM, Ondrej Certik [EMAIL PROTECTED] wrote:
On Thu, Jun 19, 2008 at 1:21 PM, tom [EMAIL PROTECTED] wrote:
I was just trying out sympy to try and make a few bits of hand-algebra
easier, and avoid mistakes, but am having some trouble.
I'm trying to factor out one
On Jun 19, 12:34 pm, Ondrej Certik [EMAIL PROTECTED] wrote:
however, generally the factor function is fragile, as you have
find out.
Ok, fair enough. Thanks - 'collect' does appear to do what I
want here. I know factorisation is a tricky problem in general,
I just wanted to get the hang of
On Jun 19, 1:20 pm, Ondrej Certik [EMAIL PROTECTED] wrote:
Right. I think you are doing it right. The other (maybe simple) option
is to use solve, here is my session where I tried that:
In [1]: vin, vout, r1, r2 = symbols([Vin, Vout, R1, R2])
In [2]: a = (vin-vout)/r1 + (0-vout)/r2
In
Hi,
I see the problem was solved, however a few comments are needed.
I'm trying to factor out one variable, so tried
(having set up a and b as symbols):
collect() works, but the same can be achieved with factor(), e.g.:
In [4]: factor(a*b+b, (a, b))
Out[4]: b*(1 + a)
or else
In [7]:
