Christophe wrote:
> FIRST QUESTION
> So why [(x0, log(x))] is not simply (x0, log(x)) ? Same
> question for [x0*(1 + x0)*cos(y) + x0**2] ?
That is how cse works. It stands for common subexpression elimination. You are
probably using it in way that is more specific that the general
Toon Verstraelen a écrit :
> That is how cse works. It stands for common subexpression elimination. You
> are
> probably using it in way that is more specific that the general purpose of
> cse.
> It might very well be that some expressions have multiple common
> subexpressions.
> Try for exa
