I would just use separatevars or factor on the expression to try to
split it apart, and then just match against x**n*y. I can't think of
any convoluted way to write x**n*y that that wouldn't work on.
Aaron Meurer
On Tue, Mar 12, 2013 at 5:50 AM, Manoj Kumar
manojkumarsivaraj...@gmail.com wrote:
I'm also not sure of the condition i.args[i] S.Zero in the list
comprehension , theres a simplify before factor , so I guess there wouldn't
be a need of that too.
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