This:
import ast
ast.parse(repr(expression))
will do the trick if repr is well coded.
How much faith should I put in the repr strings in sympy? Or there is
another way?
On 12 November 2011 18:20, krastanov.ste...@gmail.com
krastanov.ste...@gmail.com wrote:
Is there any way to get the
12.11.2011 21:42, krastanov.ste...@gmail.com пишет:
This:
import ast
ast.parse(repr(expression))
will do the trick if repr is well coded.
How much faith should I put in the repr strings in sympy? Or there is
another way?
On 12 November 2011 18:20, krastanov.ste...@gmail.com
Hi.
As far as I know, we don't have a function that does exactly that,
though I could be wrong. It would be nice to have one, though.
On Sat, Nov 12, 2011 at 11:01 AM, Alexey U. Gudchenko pr...@goodok.ru wrote:
12.11.2011 21:42, krastanov.ste...@gmail.com пишет:
This:
import ast
Ok, but why are those printed differently (ipython --profile=sympy):
In [34]: sin(x).func
Out[34]: sympy.functions.elementary.trigonometric.sin
In [35]: str(sin(x).func)
Out[35]: sin
In [39]: Integral(x, (x,0,1)).func
Out[39]: sympy.integrals.integrals.Integral
In [40]: str(Integral(x,
Hi,
On 12 November 2011 17:00, krastanov.ste...@gmail.com
krastanov.ste...@gmail.com wrote:
Ok, but why are those printed differently (ipython --profile=sympy):
In [34]: sin(x).func
Out[34]: sympy.functions.elementary.trigonometric.sin
In [35]: str(sin(x).func)
Out[35]: sin
In [39]:
Then I suppose I can just call a function that returns a string. Here is
the problem I have:
In [42]: lambdarepr(Integral(x, (x,0,1)).func)
Out[42]: class 'sympy.integrals.integrals.Integral'
In [43]: lambdarepr(Integral(x, (x,0,1)))
Out[43]: Integral(x, (x, 0, 1))
Why is out[42] not the same
Hi,
On 12 November 2011 17:16, krastanov.ste...@gmail.com
krastanov.ste...@gmail.com wrote:
Then I suppose I can just call a function that returns a string. Here is
the problem I have:
In [42]: lambdarepr(Integral(x, (x,0,1)).func)
Out[42]: class 'sympy.integrals.integrals.Integral'
In
Can the default printer be changed so lambdarepr(SomeClass(args)) and
lambdarepr(SomeClass(args).func) give always the same thing.
lambdarepr is using LambdaPrinter. What should be done there (or to a
subclass of LambdaPrinter) to ensure the behavior that I desire?
On 13 November 2011 02:21,
Hi,
On 12 November 2011 17:25, krastanov.ste...@gmail.com
krastanov.ste...@gmail.com wrote:
Can the default printer be changed so lambdarepr(SomeClass(args)) and
lambdarepr(SomeClass(args).func) give always the same thing.
lambdarepr is using LambdaPrinter. What should be done there (or to
Thank you for the information.
On 13 November 2011 02:34, Mateusz Paprocki matt...@gmail.com wrote:
Hi,
On 12 November 2011 17:25, krastanov.ste...@gmail.com
krastanov.ste...@gmail.com wrote:
Can the default printer be changed so lambdarepr(SomeClass(args)) and
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