Re: [sympy] Substitution into a derivative

2015-01-27 Thread almog yalin
That's exactly what I needed. Thanks! On Tue, Jan 27, 2015 at 7:14 PM, Aaron Meurer wrote: > Use expression.doit(). simplify() ought to be doing this as well ( > https://github.com/sympy/sympy/pull/2936 and > https://github.com/sympy/sympy/issues/6399). > > Aaron Meurer > > On Mon, Jan 26, 2015

Re: [sympy] Substitution into a derivative

2015-01-27 Thread Aaron Meurer
Use expression.doit(). simplify() ought to be doing this as well ( https://github.com/sympy/sympy/pull/2936 and https://github.com/sympy/sympy/issues/6399). Aaron Meurer On Mon, Jan 26, 2015 at 10:58 PM, almog yalin wrote: > I'm trying apply the following substitution a(x) = c * b(x) into a'(x)

[sympy] Substitution into a derivative

2015-01-26 Thread almog yalin
I'm trying apply the following substitution a(x) = c * b(x) into a'(x) a = sympy.Function('a') b = sympy.Function('b') c = sympy.Symbol('c') x = sympy.Symbol('x') expression = sympy.Derivative(a(x),x) expression = expression.subs(a(x),c*b(x)) print expression.simplify() I was expecting to get >