Thanks. Both variants are helpful!
Carsten
On 02/19/2016 08:23 PM, Aaron Meurer wrote:
> It looks like the meijerg algorithm gives the better form:
>
> In [33]: integrate(tan(x), x, meijerg=True)
> Out[33]: -log(cos(x))
>
> Aaron Meurer
>
> On Fri, Feb 19, 2016 at 2:21 PM, Ondřej Čertík
> wr
It looks like the meijerg algorithm gives the better form:
In [33]: integrate(tan(x), x, meijerg=True)
Out[33]: -log(cos(x))
Aaron Meurer
On Fri, Feb 19, 2016 at 2:21 PM, Ondřej Čertík wrote:
> On Fri, Feb 19, 2016 at 8:45 AM, Aaron Meurer wrote:
>> trigsimp() will convert the sin to cos. To r
On Fri, Feb 19, 2016 at 8:45 AM, Aaron Meurer wrote:
> trigsimp() will convert the sin to cos. To remove the negative and
> square, you'll have to use expand_log(force=True), which gives a
> complex constant (which can be ignored, since this is an integral).
>
> It would definitely be better if in
trigsimp() will convert the sin to cos. To remove the negative and
square, you'll have to use expand_log(force=True), which gives a
complex constant (which can be ignored, since this is an integral).
It would definitely be better if integrate at least gave log(1 -
sin(x)**2) so that the result is
I want to calculate the antiderivative for tan(x)
In [4]: x = sp.Symbol('x', real=True)
In [5]: sp.integrate(sp.tan(x), x)
Out[5]: -log(sin(x)**2 - 1)/2
This result is technically correct, but I would (for didactic purposes)
prefer something like
-log(cos(x)).
How can I achieve this?
Thanks.
