Thanks a lot chris for your timely help!
I hope this helps me out in my work ahead.
On Friday, 26 April 2013 01:44:21 UTC+5:30, smichr wrote:
Your tolerance is too high so you are not as close to the roots as you
would like to be. Also, whenever there is a denominator, it is better to
get
Hi,
I am trying to solve a system of 3 non linear equations with 3 variables
using `sympy.nsolve`. However, when I re substitute the values back just to
verify that the original equations are satisfied, I find out that not all
are getting satisfied, even approximately. Is there something wrong
Your tolerance is too high so you are not as close to the roots as you
would like to be. Also, whenever there is a denominator, it is better to
get rid of it as this helps the numerical process.
nsolve([numer(i.normal()).expand() for i in
(eqn1,eqn2,eqn3)],(p,q,r),(.01,
.2,18))
matrix(
