Status: New
Owner: ----
Labels: Type-Defect Priority-Medium
New issue 1561 by tom.denniston: lambdify doesn't seem to work with logic
operations
http://code.google.com/p/sympy/issues/detail?id=1561
I'm using sympy 0.6.5
I took an example from the docs on the logic module y|x&y and I tried to
use the lambdify function on it. It failed saying "Or" was undefined:
>>> x,y = sympy.symbols('x y')
>>> expr = (y | (x & y)
>>> sympy.lambdify(['x','y'],expr, modules = ['numpy'])(1,[0,1])
I can fake it by doing this, but you can see why this would be non-ideal:
>>> sympy.lambdify(['x','y','Or','And'],expr, modules = ['numpy'])(1,[0,1],
Or = numpy.logical_or, And = numpy.logical_and)
array([False, True], dtype=bool)
It seems the functionality to construct the namespace doesn't have support
for the logic operators.
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