Comment #1 on issue 1092 by plaes800: limit(sum(1/k, (k, 1, n))-log(n), n,
oo) should do it
http://code.google.com/p/sympy/issues/detail?id=1092
This at least doesn't crash anymore...
In [1]: limit(sum(1/k, (k, 1, n))-log(n), n, oo)
Out[1]: -∞ + Sum(1/k, (k, 1, n))
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Updates:
Labels: -WrongResult
Comment #11 on issue 1092 by asmeu...@gmail.com: limit(sum(1/k, (k, 1,
n))-log(n), n, oo) should do it
http://code.google.com/p/sympy/issues/detail?id=1092
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Comment #12 on issue 1092 by smi...@gmail.com: limit(sum(1/k, (k, 1,
n))-log(n), n, oo) should do it
http://code.google.com/p/sympy/issues/detail?id=1092
This now returns
limit(summation(1/k, (k, 1, n))-log(n), n, oo)
Traceback (most recent call last):
File "", line 1, in
File "sympy\
Updates:
Status: Started
Owner: someb...@bluewin.ch
Comment #13 on issue 1092 by someb...@bluewin.ch: limit(sum(1/k, (k, 1,
n))-log(n), n, oo) should do it
http://code.google.com/p/sympy/issues/detail?id=1092
(No comment was entered for this change.)
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Comment #14 on issue 1092 by gra...@gmail.com: limit(sum(1/k, (k, 1,
n))-log(n), n, oo) should do it
http://code.google.com/p/sympy/issues/detail?id=1092
Currently, it returns the correct limit
from sympy import *
k = Symbol('k')
n = Symbol('n')
limit(summation(1/k, (k, 1, n))-log(n), n
Updates:
Status: Fixed
Comment #15 on issue 1092 by asmeu...@gmail.com: limit(sum(1/k, (k, 1,
n))-log(n), n, oo) should do it
http://code.google.com/p/sympy/issues/detail?id=1092
Bisected to
commit 70243d5e83121e0d49ad0970e96adf27d952333a
Author: Raoul Bourquin
Date: Sat Feb 23 19
Comment #3 on issue 1092 by smi...@gmail.com: limit(sum(1/k, (k, 1,
n))-log(n), n, oo) should do it
http://code.google.com/p/sympy/issues/detail?id=1092
This gives -oo in master and can probably be closed. I believe what happens
is the Sum cannot be evaluated as being unbounded so it gets p
Comment #4 on issue 1092 by asmeurer: limit(sum(1/k, (k, 1, n))-log(n), n,
oo) should do it
http://code.google.com/p/sympy/issues/detail?id=1092
Isn't the answer finite, though? Isn't that Euler's gamma constant?
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Labels: WrongResult
Comment #5 on issue 1092 by asmeurer: limit(sum(1/k, (k, 1, n))-log(n), n,
oo) should do it
http://code.google.com/p/sympy/issues/detail?id=1092
Just to note: it should be summation() now, i.e., limit(summation(1/k, (k,
1, n))-log(n), n, oo).
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Comment #6 on issue 1092 by asmeurer: limit(sum(1/k, (k, 1, n))-log(n), n,
oo) should do it
http://code.google.com/p/sympy/issues/detail?id=1092
We have EulerGamma implemented already, btw:
In [12]: EulerGamma
Out[12]: EulerGamma
In [13]: EulerGamma.evalf()
Out[13]: 0.577215664901533
And i
Updates:
Labels: smichr NeedsReview
Comment #7 on issue 1092 by smi...@gmail.com: limit(sum(1/k, (k, 1,
n))-log(n), n, oo) should do it
http://code.google.com/p/sympy/issues/detail?id=1092
In [ https://github.com/sympy/sympy/pull/61 ] this now gives
h[1] >>> limit(summation(1/k,
Updates:
Labels: -smichr -NeedsReview
Comment #8 on issue 1092 by smi...@gmail.com: limit(sum(1/k, (k, 1,
n))-log(n), n, oo) should do it
http://code.google.com/p/sympy/issues/detail?id=1092
The changes referred to in the previous comment are commited, but the issue
is being left op
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