On Wed, Feb 13, 2013 at 08:07:07PM +0100, Lennart Poettering wrote:
> On Wed, 13.02.13 20:05, Zbigniew Jędrzejewski-Szmek (zbys...@in.waw.pl) wrote:
>
> > Actually, the syntax already is _not_ a subset of the shell, and has its
> > own pecularities. Anyone trying to blindly follow shell rules is g
On Wed, Feb 13, 2013 at 4:26 PM, Kay Sievers wrote:
> On Wed, Feb 13, 2013 at 9:52 PM, Zbigniew Jędrzejewski-Szmek
> wrote:
>> On Wed, Feb 13, 2013 at 08:07:07PM +0100, Lennart Poettering wrote:
>>> On Wed, 13.02.13 20:05, Zbigniew Jędrzejewski-Szmek (zbys...@in.waw.pl)
>>> wrote:
>>>
>>> > Actu
On Wed, Feb 13, 2013 at 9:52 PM, Zbigniew Jędrzejewski-Szmek
wrote:
> On Wed, Feb 13, 2013 at 08:07:07PM +0100, Lennart Poettering wrote:
>> On Wed, 13.02.13 20:05, Zbigniew Jędrzejewski-Szmek (zbys...@in.waw.pl)
>> wrote:
>>
>> > Actually, the syntax already is _not_ a subset of the shell, and h
On Wed, Feb 13, 2013 at 08:07:07PM +0100, Lennart Poettering wrote:
> On Wed, 13.02.13 20:05, Zbigniew Jędrzejewski-Szmek (zbys...@in.waw.pl) wrote:
>
> > Actually, the syntax already is _not_ a subset of the shell, and has its
> > own pecularities. Anyone trying to blindly follow shell rules is g
On Wed, 13.02.13 20:05, Zbigniew Jędrzejewski-Szmek (zbys...@in.waw.pl) wrote:
> Actually, the syntax already is _not_ a subset of the shell, and has its
> own pecularities. Anyone trying to blindly follow shell rules is going
> to be severly bitten anyway. So, why not go a bit further and change
On Wed, Feb 13, 2013 at 07:41:54PM +0100, Lennart Poettering wrote:
> On Wed, 13.02.13 05:26, Zbigniew Jędrzejewski-Szmek (zbys...@in.waw.pl) wrote:
>
> >
> > On Wed, Feb 13, 2013 at 04:27:49AM +0100, Lennart Poettering wrote:
> > > On Thu, 07.02.13 11:45, Michal Vyskocil (mvysko...@suse.cz) wrot
On Wed, 13.02.13 05:26, Zbigniew Jędrzejewski-Szmek (zbys...@in.waw.pl) wrote:
>
> On Wed, Feb 13, 2013 at 04:27:49AM +0100, Lennart Poettering wrote:
> > On Thu, 07.02.13 11:45, Michal Vyskocil (mvysko...@suse.cz) wrote:
> >
> > > Commented lines are ignored by default and are considered as end
On Wed, Feb 13, 2013 at 04:27:49AM +0100, Lennart Poettering wrote:
> On Thu, 07.02.13 11:45, Michal Vyskocil (mvysko...@suse.cz) wrote:
>
> > Commented lines are ignored by default and are considered as end of a
> > definition. If they ends on a backslash, they are just ignored and a
> > next lin
On Thu, 07.02.13 11:45, Michal Vyskocil (mvysko...@suse.cz) wrote:
> Commented lines are ignored by default and are considered as end of a
> definition. If they ends on a backslash, they are just ignored and a
> next line is considered as a part of a definition.
I am pretty sure that continuation
Commented lines are ignored by default and are considered as end of a
definition. If they ends on a backslash, they are just ignored and a
next line is considered as a part of a definition.
FOO=one \
two
will be evaluated as FOO="one two", where
FOO=one \
two
will result in FOO="one" and two.
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