Docs don't even need uri's. ... That's where the fun really starts in info space
Sent from my iPad (excuse the terseness)
David A Lee
d...@calldei.com
> On Jan 5, 2014, at 9:16 PM, "Liam R E Quin" wrote:
>
>> On Sun, 2014-01-05 at 22:23 +, David Lee wrote:
>> Seems there is no guarantee t
On Sun, 2014-01-05 at 22:23 +, David Lee wrote:
> Seems there is no guarantee that
>uri-collection()!doc(.) produces the same results as collection()
Right - collection() really marks the border of what we (W3C) could
standardize at the time, when many implementations of XQuery do not (f
Re: fn:uri-collection() !!
Another new function for me ... looks useful If/and/only/if it correlates to
what you want ...
Seems there is no guarantee that
uri-collection()!doc(.) produces the same results as collection()
this is a broad field, that incidentally I think is underappreciated.
Thanks.
Not even knowing of the existence of fn:filter or fn:for-each-pair I wrote just
now my version in old-fashioned-xquery
declare function common:node-index-of( $nodes as node()* , $node as node() ) as
xs:integer ?
{
for $n at $pos in $nodes
return
if( $n is $node )
On 5 January 2014 21:20, Michael Kay wrote:
>
> On 5 Jan 2014, at 20:59, David Lee wrote:
>
>> Given those truths ...
>> If you do have a sequence from fn:collection() or another function you *can*
>> find the position of a document in that collection and its 'sibling'
>>
>> Note: this may be a
On 5 Jan 2014, at 21:24, David Lee wrote:
> Arg ... so your saying index-of causes a string atomization ?
> Ug. I know it wants item* and uses "eq" as the comparison but didn't
> realize that would stringify documents ...
Actually the function signature for index-of expects xs:anyAtomicType
Arg ... so your saying index-of causes a string atomization ?
Ug. I know it wants item* and uses "eq" as the comparison but didn't realize
that would stringify documents ...
Do you know of a sequence function that uses document or node ID's ?
David
On 5 Jan 2014, at 20:59, David Lee wrote:
> Given those truths ...
> If you do have a sequence from fn:collection() or another function you *can*
> find the position of a document in that collection and its 'sibling'
>
> Note: this may be a horribly inefficient thing to do so buyer beware
Given those truths ...
If you do have a sequence from fn:collection() or another function you *can*
find the position of a document in that collection and its 'sibling'
Note: this may be a horribly inefficient thing to do so buyer beware
let $c := fn:collection(),
$doc := local:pick-a
On 5 Jan 2014, at 16:50, Ihe Onwuka wrote:
> If x is the document element of a document in a collection, is it the sibling
> of y that is the document element of another document in the same collection?
No.
>
> If not why not?
"Why" questions are very difficult to answer. Do you want a histo
At 2014-01-05 16:50 +, Ihe Onwuka wrote:
If x is the document element of a document in a collection, is it
the sibling of y that is the document element of another document in
the same collection?
If not why not?
It doesn't, because the specification says it doesn't:
http://www.w3.org
XPath axes only operate within the bounds of a single document.
On Sun, Jan 5, 2014 at 11:38 AM, Ihe Onwuka wrote:
> Certainly in the XPath sense and why not in the general sense (whatever that
> means).
>
>
> On Sun, Jan 5, 2014 at 5:36 PM, Joe Wicentowski wrote:
>>
>> Do you mean "sibling" in
Certainly in the XPath sense and why not in the general sense (whatever
that means).
On Sun, Jan 5, 2014 at 5:36 PM, Joe Wicentowski wrote:
> Do you mean "sibling" in the sense of the XPath axes preceding-sibling
> and following-sibling, or in the general sense of documents being
> "children" o
Do you mean "sibling" in the sense of the XPath axes preceding-sibling
and following-sibling, or in the general sense of documents being
"children" of a "parent" collection and thus "siblings"?
On Sun, Jan 5, 2014 at 10:50 AM, Ihe Onwuka wrote:
> If x is the document element of a document in a co
If x is the document element of a document in a collection, is it the
sibling of y that is the document element of another document in the same
collection?
If not why not?
___
talk@x-query.com
http://x-query.com/mailman/listinfo/talk
15 matches
Mail list logo
