it should not. If this cause problem, it should raise an error. upd isn't a
normal python dict, but a special class that will make sure we don't loose
updates and give an error if the user would cause that behavior.
On Wed, Nov 23, 2016 at 3:13 PM, Shir Gur wrote:
> Will it ruin the update dicta
Will it ruin the update dictation of the scan procedure?
On Wednesday, November 23, 2016 at 9:07:53 PM UTC+2, nouiz wrote:
>
> upd[W] = m
>
> should work.
>
> Fred
>
> On Wed, Nov 23, 2016 at 12:39 PM, Shir Gur > wrote:
>
>> Hi,
>>
>> i have my scan function, something like
>>
>> def _loop(i):
>>
upd[W] = m
should work.
Fred
On Wed, Nov 23, 2016 at 12:39 PM, Shir Gur wrote:
> Hi,
>
> i have my scan function, something like
>
> def _loop(i):
> x = something with shared varibale W
> return x, {W:x}
>
>
> res, upd = theano.scan(fn=_loop, sequence=T.arange(10))
>
>
> so after each
Hi,
i have my scan function, something like
def _loop(i):
x = something with shared varibale W
return x, {W:x}
res, upd = theano.scan(fn=_loop, sequence=T.arange(10))
so after each iteration the scan function updates *W* to be *x*.
Now i have the following:
m = T.argmx(res)
func =
Hi,
i have my scan function, something like
def _loop(i):
x = something with shared varibale W
return x, {W:x}
res, upd = theano.scan(fn=_loop, sequence=T.arange(10))
so after each iteration the scan function updates *W* to be *x*.
Now i have the following:
m = T.argmx(res)
func =
