Re: [time-nuts] New pics of RFTG-m-Rb, and some comparison details

2006-12-31 Thread Jason Rabel
David, Your thinking pretty much along the same lines as me from your post. FYI, I didn't mean the XO itself, I meant the "XO module" (specifically the GPS/PPS signal). There is also a "RFTG-u REF 0" on eBay, however the picture is so poor I can't make out all the connections. But it too has the

Re: [time-nuts] New pics of RFTG-m-Rb, and some comparison details

2006-12-31 Thread Jason Rabel
The RFG-XO doesn't have a GPS unit in it. It has a 10 MHz in, and of course the 15 MHz out. It also only has three DB9 connection, the 24V, interface, and alarm It is missing the RS-485/1PPS connection. Similar the RFG-RB doesn't have the RS-485/1PPS connection. > I just got an RFG-RB which s

Re: [time-nuts] New pics of RFTG-m-Rb, and some comparison details

2006-12-31 Thread Jason Rabel
The two units go in (what was told to me) an open frame chassis, it has SMA and I believe DB-15 connections along the top. The connections on the chassis split the signals even more, presumably for routing to the rest of the cell. http://campus.pari.edu/k4cso/gps/Lucent/ I was able to contact the

Re: [time-nuts] New pics of RFTG-m-Rb, and some comparison details

2006-12-31 Thread Bill Hawkins
So, if we have two sources of 15 MHz in a CDMA minicell, each with its own SMA connector, what module receives those two sources and decides which one to use? Why use XO and Rb when either could be made redundant for extended reliability? (not the British sense of "made redundant") Bill Hawkins

Re: [time-nuts] New pics of RFTG-m-Rb, and some comparison details

2006-12-31 Thread Rex
On Sun, 31 Dec 2006 09:22:50 -0600, "Jason Rabel" <[EMAIL PROTECTED]> wrote: >Pretty sure that the RB is disciplined from the XO through the interface >cable. I posted the pinout a couple times before so people can make their >own. I don't so. I think the RB units have just their factory calibrat

Re: [time-nuts] New pics of RFTG-m-Rb, and some comparison details

2006-12-31 Thread David I. Emery
On Sun, Dec 31, 2006 at 09:22:50AM -0600, Jason Rabel wrote: > Pretty sure that the RB is disciplined from the XO through the interface > cable. I posted the pinout a couple times before so people can make their > own. While I may have too much shoe leather in mouth to think clearly, it se

Re: [time-nuts] New pics of RFTG-m-Rb, and some comparison details

2006-12-31 Thread Jason Rabel
Pretty sure that the RB is disciplined from the XO through the interface cable. I posted the pinout a couple times before so people can make their own. As for the 10 MHz on the Rb Why not just get a mini-circuits splitter (cheap on eBay) so you have the 10 MHz from the RB and can still run it

Re: [time-nuts] New pics of RFTG-m-Rb, and some comparison details

2006-12-31 Thread Didier Juges
If the unit has an internal 10 MHz OCXO, it is hard to imagine the 15 MHz being cleaner than the 10 MHz, so it would seem the best way (simpler and cleaner) is actually to tap off the OCXO with a suitable buffer amp. Didier KO4BB jmfranke wrote: > One approach would be to divide the 15 MHz by

Re: [time-nuts] New pics of RFTG-m-Rb, and some comparison details

2006-12-31 Thread jmfranke
One approach would be to divide the 15 MHz by three and then mix the resultant 5 MHz with the original 15 MHz to get 10 MHz: original minus one third equals two thirds. John WA4WDL - Original Message - From: "John Ackermann N8UR" <[EMAIL PROTECTED]> To: "Discussion of precise time and

Re: [time-nuts] New pics of RFTG-m-Rb, and some comparison details

2006-12-31 Thread John Ackermann N8UR
Bill Hawkins said the following on 12/31/2006 02:15 AM: > Anybody know how to divide by 2/3rds without a microprocessor? :-) I suspect it would be pretty easy to tap off the 10MHz signal from the XO in addition to (or instead of) the 15MHz output. John __

Re: [time-nuts] New pics of RFTG-m-Rb, and some comparison details

2006-12-31 Thread Dr Bruce Griffiths
Hal Murray wrote: >> If you mean multiply the 15MHz output by 2/3 to generate 10MHz, simply >> use asynchronous divide by 3 counter (2 fliplops) to produce a 5MHz 1/ >> 3 duty cycle (or 2/3) output then filter out the 10MHz 2nd harmonic >> component with a bandpass filter. The 3rd Harmonic (15MHz

Re: [time-nuts] New pics of RFTG-m-Rb, and some comparison details

2006-12-31 Thread David I. Emery
On Sat, Dec 30, 2006 at 02:24:32PM -0500, John Ackermann N8UR wrote: > On the mezzanine board, U302, a Burr Brown ADS7807U (presumably an ADC, > though I haven't looked it up yet) is present on the XO version, but > missing on the Rb version. And, programmable device U103 has a > different number.

Re: [time-nuts] New pics of RFTG-m-Rb, and some comparison details

2006-12-31 Thread Hal Murray
> If you mean multiply the 15MHz output by 2/3 to generate 10MHz, simply > use asynchronous divide by 3 counter (2 fliplops) to produce a 5MHz 1/ > 3 duty cycle (or 2/3) output then filter out the 10MHz 2nd harmonic > component with a bandpass filter. The 3rd Harmonic (15MHz) will > conveniently

Re: [time-nuts] New pics of RFTG-m-Rb, and some comparison details

2006-12-31 Thread David I. Emery
On Sun, Dec 31, 2006 at 01:15:12AM -0600, Bill Hawkins wrote: > Ah, well. I have also received two Lucent KS-24019 L106B, aka > RFTG-m-XO boxes. The serial numbers indicate 95 and 96 construction. > The assembly numbers, 55761ASSY103902-001 (55761 is the CAGE number > for Efratom) have Rev E, S/N 5