RE: JK2 LB_FACTOR problem

2004-04-09 Thread Angus Mezick
Back to that march 1 post. > 1. lb_value += lb_factor Ok, I see this I think. But this happens after step 2. > 2. the highest lb_value gets server; Am I reading this code wrong, or is it the LOWEST value that is getting the server /** Get one worker that is ready */ for( level=0;

RE: JK2 LB_FACTOR problem

2004-03-01 Thread Mladen Turk
> -Original Message- > From: Angus Mezick > Why the heck to the workers with a lb_factor of 1 get a > lb_value of 19[1-2]? What is lb_value? I am expecting for > ever 104 requests worker > 3 will get 100 of them and workers 2,4,5,6 will get 1 each. > Am I wrong? default lb_factor