Re: [topbraid-users] How to retrieve taxonomies' status value/label

2018-10-30 Thread William Ramos
Thanks, Holger, this is very useful. -- You received this message because you are subscribed to the Google Groups "TopBraid Suite Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to topbraid-users+unsubscr...@googlegroups.com. For more options, visit

Re: [topbraid-users] How to retrieve taxonomies' status value/label

2018-10-29 Thread Holger Knublauch
Hi William, you would get all properties if you simply delete the FILTER statement. Or do I misunderstand your question? On the BIND statements, note that the human-readable display label of these properties are stored in a different graph than ?projectGraph. You may want to switch to    

Re: [topbraid-users] How to retrieve taxonomies' status value/label

2018-10-29 Thread William Ramos
Yes, that works exactly as I was expecting, thanks a lot, Holger. *Could you please help me with another question?* In my project we are aiming to create a JSON SWON service which returns all the values from the taxonomies' metadata. Currently we have an SPARQL statement that goes like this: SEL

Re: [topbraid-users] How to retrieve taxonomies' status value/label

2018-10-28 Thread Holger Knublauch
Does this address your question: SELECT ?projectGraph ?status ?statusLabel WHERE {     rdf:nil teamwork:graphsUnderTeamControl ( ?projectGraph ) .     GRAPH ?projectGraph {     ?projectGraph a .     ?projectGraph