Hi,
I've written a macro that takes RDF and converts it to HTML and
inserts it in a wiki page.
The macro will take an attachment on the current page and render it,
it works like this:
[[RdfView(example.rdf)]]
In my macro code, I've figured out how to get the filename, but I need
the actual path to it (not URL) so I can open it and run it through an
RDF parser.
def expand_macro(self, formatter, name, content):
#'content' is the attachment filename
So I need to do something like os.path.join(SOME_FUNCTION(), content))
What function will give me that path?
Thanks,
Rob
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups "Trac
Users" group.
To post to this group, send email to trac-users@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
http://groups.google.com/group/trac-users?hl=en
-~----------~----~----~----~------~----~------~--~---
