How would I best turn this string:
'2005-01-24 00:00:00.0'
into this string:
'2005%2D01%2D24%2000%3A00%3A00%2E0'
In order to call a URL.
I've hunted through the standard library, but nothing seemed to jump out.
Thank You.
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On Jan 24, 2005, at 23:29, Luis N wrote:
How would I best turn this string:
'2005-01-24 00:00:00.0'
into this string:
'2005%2D01%2D24%2000%3A00%3A00%2E0'
In order to call a URL.
I've hunted through the standard library, but nothing seemed to jump
out.
The pathname2url in urllib seems to do
I got this from spyce
http://spyce.sourceforge.net
_url_ch = re.compile(r'[^A-Za-z0-9_.!~*()-]') # RFC 2396 section 2.3
def url_encode(o, **kwargs):
'''Return URL-encoded string.'''
return _url_ch.sub(lambda match: %%%02X % ord(match.group(0)),
str(o))
It was just the first thing I found in
Luis N wrote:
How would I best turn this string:
'2005-01-24 00:00:00.0'
into this string:
'2005%2D01%2D24%2000%3A00%3A00%2E0'
In order to call a URL.
urllib.quote_plus() is intended for this purpose though it doesn't have the
result you ask for:
import urllib
s='2005-01-24 00:00:00.0'
Kent Johnson wrote:
import re
def hexify(match):
... return '%%%X' % ord(match.group(0))
Ah, should be '%%%02X' ...
Kent
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Kent Johnson kent37 at tds.net writes:
[snip]
You still aren't doing anything with newdic. The absence of 'newdic' in the
code
after 'read.close()' should be a clue
I think you want to overwrite the saved dict, but with the new dict instead
of
with a filename string...
Hi Kent,
