You are getting these errors because the API for Python varies by
release (e.g. 2.4 to 2.5) due to additions, bug fixes, etc.. The
warning you are receiving is letting you know that it was compiled and
meant to be run on Python 2.4, and also subtly warning that problems
may arise when you run or
hello, I just upgraded to python 2.5 and wxpython 2.6. I'm not sure the correct
list for this but I'm trying to shove some variables into a py shell using the
below code. this worked pretty well before, but now it gives me an error on the
last line of my brief example. The error is:
'dict'
hello from a programming newbie.
I am writing a metronome function.
Currently, I am using a hack with the system bell:
[code]
def tick(rate):
while true: #do until
C-c
print '\a' #system bell inside
terminal
time.sleep(rate) #pause at desired
rate
[/code]
I would like to use an
RE leaves me totally confuzzzeddded. Yep, so confuised I'm having
trouble spelling it. Sp this one line will replace both words and give a
reliable result?
Barnaby Scott wrote:
[snip]
> No idea if it has anything to do with your problem, but it struck me
> that the iswikiword() function (and pr
Kent Johnson wrote:
> Smith, Jeff wrote:
>
>> I'm getting use to using list iteration and comprehension but still have
>> some questions.
>>
>> 1. I know to replace
>> for i in range(len(list1)):
>> do things with list1[i]
>> with
>> for li in list1:
>> do things with li
On 2/25/07, Dave Kuhlman <[EMAIL PROTECTED]> wrote:
> If you have not already, you will want to look at SWIG
> (http://www.swig.org/). SWIG will generate C or C++ code from a
> header file containing structs and classes and function
> declarations. That generated code can then be compiled and lin
On Sat, Feb 24, 2007 at 02:50:41AM -0800, Dj Gilcrease wrote:
> I am attempting to embed Python in a C++ app and have a question
> before I get too far into it.
>
> Is is possible to to dynamically create an extension module?
> eg, I want a module name spam and I have a stuct that contains all my
David Perlman schrieb:
> I found this by "using Google". You should be able to make a simple
> modification (I can think of a couple of ways to do it) to have it
> pad the end with "None". It is 100% iterator input and output.
>
> http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/30327
Smith, Jeff wrote:
> I'm getting use to using list iteration and comprehension but still have
> some questions.
>
> 1. I know to replace
> for i in range(len(list1)):
> do things with list1[i]
> with
> for li in list1:
> do things with li
> but what if there are two lists t
I'm getting use to using list iteration and comprehension but still have
some questions.
1. I know to replace
for i in range(len(list1)):
do things with list1[i]
with
for li in list1:
do things with li
but what if there are two lists that you need to access in sync. Is
the
I found this by "using Google". You should be able to make a simple
modification (I can think of a couple of ways to do it) to have it
pad the end with "None". It is 100% iterator input and output.
http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/303279
On Feb 25, 2007, at 7:06 AM, C
Keep in mind that things generally become extremely reliable only
after extensive real-world testing. TANSTAAFL
On Feb 25, 2007, at 1:14 AM, Kirk Bailey wrote:
> This has to be baby carriage reliable and simple for the business road
> warrior who has not a geekified bone in their body.
--
Luke Paireepinart schrieb:
> Christopher Arndt wrote:
>> I have tried to find a solution, using itertools, but I'm not very
>> experienced in functional stuff, so I got confused.
> Do you mean you're not experienced in using functions or do you mean
> you're inexperienced at functional programmin
Christopher Arndt wrote:
> Given a sequence, how can I group it pairwise, so that I get
>
> [(s0, s1), (s2, s3), ... , (sn-1, sn)]
>
> or, if len(s)%2 != 0
>
> [(s0, s1), (s2, s3), ... , (sn, None)]
>
>
> I have tried to find a solution, using itertools, but I'm not very
> experienced in functional
Given a sequence, how can I group it pairwise, so that I get
[(s0, s1), (s2, s3), ... , (sn-1, sn)]
or, if len(s)%2 != 0
[(s0, s1), (s2, s3), ... , (sn, None)]
I have tried to find a solution, using itertools, but I'm not very
experienced in functional stuff, so I got confused. There is a reci
"Kirk Bailey" <[EMAIL PROTECTED]> wrote
> couple. A solid and drool-proof server is the remaining leg of the
Take a look at xitami
http://www.xitami.com/download.htm
Free, small, flexible, configurable and fast being written in C.
HTH,
Alan G.
16 matches
Mail list logo