well i made a mistake again :P. i have the function x ^ 1/3, i first
remembered that negative numbers do not have a square, but in this case
negative numbers are ok...because it aint 1/2 ...its 1/3. Can anyone
give a hint of how i can calculate it without using pow ou **? none of
them work properly
ops, now i realize the mistake i was making. Thanks for the help people
Tiago Katcipis escreveu:
> im not understanding why is this a problem...i have this simple function
>
> def newton_divergente(x):
> return math.pow(x, 1.0/3.0)
>
> but when x = -20 it returns this error
>
> return math.pow(
On 21/04/2008, John Fouhy <[EMAIL PROTECTED]> wrote:
> >>> -1 ** (1.0/2.0)
> -1.0
Replying to myself:
It turns out that all is not what it seems. Let's try again:
>>> (-1)**0.5
Traceback (most recent call last):
File "", line 1, in
ValueError: negative number cannot be raised to a fraction
On 21/04/2008, Tiago Katcipis <[EMAIL PROTECTED]> wrote:
> im not understanding why is this a problem...i have this simple function
>
> def newton_divergente(x):
> return math.pow(x, 1.0/3.0)
>
> but when x = -20 it returns this error
>
> return math.pow(x, 1.0/3.0)
> ValueError: math domain
Tiago Katcipis wrote:
> im not understanding why is this a problem...i have this simple function
>
> def newton_divergente(x):
> return math.pow(x, 1.0/3.0)
>
> but when x = -20 it returns this error
>
> return math.pow(x, 1.0/3.0)
> ValueError: math domain error
>
> but why is that? is it i
im not understanding why is this a problem...i have this simple function
def newton_divergente(x):
return math.pow(x, 1.0/3.0)
but when x = -20 it returns this error
return math.pow(x, 1.0/3.0)
ValueError: math domain error
but why is that? is it impossible to calculate -20 ^ (1/3) ?
here o
"R. Alan Monroe" <[EMAIL PROTECTED]> wrote
> Given a list of 6-letter words:
> ['abject','poetry','keypad']
>
> How do I derive this list:
> ['apk', 'boe', 'jey']
>>> a = ['abject', 'poetry', 'keypad']
>>> zip( a[0],a[1],a[2])
[('a', 'p', 'k'), ('b', 'o', 'e'), ('j', 'e', 'y'), ('e', 't', 'p'),
> R. Alan Monroe wrote:
>> def checksolution(sol):
>> maybes = []
>> big = ''.join(solution)
>> for x in range(len(sol)):
>> maybes.append( big[x::6] )
>> print maybes
>>
>> solution=['abject','poetry','keypad']
>> checksolution(solution)
>>
>> ['apk', 'boe', 'jey']
> Th
R. Alan Monroe wrote:
> def checksolution(sol):
> maybes = []
> big = ''.join(solution)
> for x in range(len(sol)):
> maybes.append( big[x::6] )
> print maybes
>
> solution=['abject','poetry','keypad']
> checksolution(solution)
>
> ['apk', 'boe', 'jey']
That's nice. Why
> Given a list of 6-letter words:
> ['abject','poetry','keypad']
> How do I derive this list:
> ['apk', 'boe', 'jey']
> (The original list's first letters, second letters, third letters,
> etc.)
> I have a text file of 15280 six-letter words and I want to robotically
> generate 6x6 word squares.
Given a list of 6-letter words:
['abject','poetry','keypad']
How do I derive this list:
['apk', 'boe', 'jey']
(The original list's first letters, second letters, third letters,
etc.)
I have a text file of 15280 six-letter words and I want to robotically
generate 6x6 word squares.
My first attem
"Monika Jisswel" <[EMAIL PROTECTED]> wrote
> confused & maybe lost. my choice to go python was because i could
> feel its
> power from the first applications I could develop, then were able to
> modify
> (in no time), expand (with no single problem & in no time) ... I
> want to
> feel the same
Hi,
Ok, so if you were to go back in time ... which pythonic web-tool /framework
would you put more time in studying ? keep in mind that you still have no
experience and you need something to get you started in web technology,
second thing to take into account is that it doesn't have to be a
Hi Martin,
print 'status:', response.status
> print 'reason:', response.reason
> print 'document:', response.read()
>
This is definitly what i was looking for and did not know in which module to
look.
Thank you so much for the code illusration.
Monika.
2008/4/20, Martin Walsh <[EMAIL PROTECTED
Monika Jisswel wrote:
> Hi,
>
> can i stop urllib2.urlopen() from following redirects automatically ?
It doesn't answer your question directly, but if you care more about the
initial request/response than the content at the other end of a redirect
-- you can use httplib. It might look something
> "kinuthia muchane" <[EMAIL PROTECTED]> wrote
>
> > I do not know what I am doing wrong. When I run the following code
> > from
> > the Python prompt it executes without a murmur. But when I save it
> > as
> > a .py file and try to execute it from the shell, it just returns the
> > prompt...ac
On Sat, 2008-04-19 at 16:06 -0400, bob gailer wrote:
> kinuthia muchane wrote:
> > Hi,
> >
> > I do not know what I am doing wrong. When I run the following code from
> > the Python prompt it executes without a murmur. But when I save it as
> > a .py file and try to execute it from the shell, it j
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