Hello all,
I have dictionary like the following:
d={(1,23A):[a,b,c,d], (1,24A):[b,c,d], (2,23A):[a,b], (2,24A):[a,b,c,d]}
I would like to iterate through the dictionary such that if it finds
the value 'a' in the values of the key that it would remove the value
'b' from the values list. In addit
Hi,
I would really appreciate if someone help to find a way to calculate
delta (diff) between two similar text files. I have looked at difflib
and found related script at this site
http://www.java2s.com/Code/Python/Utility/Printfilediffsincontextunifiedorndiffformats.htm
Is there a simple way to
Kent,
On Wed, 14 May 2008, Kent Johnson wrote:
I understand about removing elements from a container you're iterating. Is
data.remove(x) problematic in this context?
Yes. It can cause the iteration to skip elements ofthe list. Better to
post-process the list with a list comprehension:
evts = [
On Wed, May 14, 2008 at 9:06 PM, Kent Johnson <[EMAIL PROTECTED]> wrote:
>> I understand about removing elements from a container you're iterating. Is
>> data.remove(x) problematic in this context?
>
> Yes. It can cause the iteration to skip elements of the list.
For example:
In [1]: l=range(5)
I
On Wed, May 14, 2008 at 6:03 PM, Jon Crump <[EMAIL PROTECTED]> wrote:
> def events(data):
> evts = []
> for x in data:
>for y in data:
> if (x['placename'] == y['placename']) and (x['end'].month + 1 ==
> y['start'].month) and (y['start'] - x['end'] == datetime.timedelta(1)):
>x['
Bob, and Kent, Many thanks!
Sounds like the key 'processed' is created by the assignment x['processed'] =
True. So those dictionaries that have not experienced this assignment have no
such key. You should instead use: if 'processed' in x:
Doh! Now that WAS obvious
Try lst.remove(x)
Now t
On Wed, May 14, 2008 at 3:02 PM, Jon Crump <[EMAIL PROTECTED]> wrote:
> Something basic about lists and loops that I'm not getting here.
> I have a function that searches through them to find pairs of dictionaries
> that satisfy certain criteria. When the nested loops find such a pair, I
> need to
Jon Crump wrote:
Something basic about lists and loops that I'm not getting here. I've
got a long list of dictionaries that looks like this:
lst = [{'placename': u'Stow, Lincolnshire', 'long-name': u'Stow,
Lincolnshire.', 'end': datetime.date(1216, 9, 28), 'start':
datetime.date(1216, 9, 26)}
Something basic about lists and loops that I'm not getting here. I've got
a long list of dictionaries that looks like this:
lst = [{'placename': u'Stow, Lincolnshire', 'long-name': u'Stow,
Lincolnshire.', 'end': datetime.date(1216, 9, 28), 'start':
datetime.date(1216, 9, 26)},
{'placename': u'
kinuthia muchane wrote:
On Tue, 2008-05-13 at 11:09 -0400, "Simón A. Ruiz" wrote:
When i is 3, then we'll only check (2 % 3 == 0) which is False, so the
loop ends unbroken and runs the else clause letting us know that 3 is
indeed a prime number.
Shouldn't we be checking for (3%2 == 0) instead
On Tue, May 13, 2008 at 9:07 PM, <[EMAIL PROTECTED]> wrote:
>
>
> def movieu(self):
> mov_name = "video.mpg"
> pygame.mixer.quit()
> screen = pygame.display.set_mode((320, 240))
> video = pygame.movie.Movie(mov_name)
> screen = pygame.display.set_mode(v
On Wed, May 14, 2008 at 3:45 AM, Mark <[EMAIL PROTECTED]> wrote:
> i want to set the keys of the user row as the keys of User self
> but i m not sure how to do it
>
> for i in self._user.keys():
> self[i]=self._user[i]
Should be
setattr(self, i, self._user[i])
> You ca
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I will respond to your message when I return.
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im trying to create a class user
so that
i can do
r=User(1)
r._user.keys()
['rating', 'last_name', 'pageviews', 'ip', 'number_polls', 'site',
'myrand', 'hotmail', 'number_activities', 'skype', 'id', 'city',
'rawpassword', 'number_useraudios', 'zip', 'number_votes',
'last_login', 'number_u
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