Hi everyone,
I'm having trouble with an anagram generating program that I am writing
in Python. My output is not what it should be and I think the reason
has something to do with my helper functions creating a reference to a
dictionary each time it is called rather than a new "clone" dictionar
> Do you want to use optparse, or get the command line arguments yourself?
> It seems the pattern string will be the first arg, will it?
Again I am confused. I assumed that optparse was the best way to pass in
arguments (such as filenames) from the command line. Like so:
./script.py -x r
Le samedi 27 décembre 2008 à 14:55 -0500, Matt Herzog a écrit :
> On Wed, Dec 24, 2008 at 01:12:55AM -, Alan Gauld wrote:
> >
> > "Kent Johnson" wrote
> >
> > >> for filename in os.listdir(directory):
> > >> result = re.match(s, filename)
> > >> print result
> > >
> > >You
On Wed, Dec 24, 2008 at 01:12:55AM -, Alan Gauld wrote:
>
> "Kent Johnson" wrote
>
> >> for filename in os.listdir(directory):
> >> result = re.match(s, filename)
> >> print result
> >
> >You never open and read the files. You are searching for the pattern
> >in the filenam
On Sat, Dec 27, 2008 at 3:42 AM, Alan Gauld wrote:
>
> Its C rather than C++.
> The <> in include statements are a variation on the "" which can also be
> used.
> The differences are subtle and have to do with the search path I think. But
> its
> been so long since I did serious C/++ I can't recal
"prasad rao" wrote
http://svn.python.org/view/python/trunk/Objects/listobject.c?rev=67498&view=markup
Kent ! This is grek and latin to me.From the presence of header
files it
looks C++.But headerfiles are not between '<' and '>' .
Its C rather than C++.
The <> in include statements are
