On Thu, Dec 5, 2013 at 9:43 AM, Jared Nielsen wrote:
> I want to create a dictionary, assign it keys, then iterate through a for
> loop and assign the dictionary values from a list. I'm trying this, but
> it's not working:
>
> dictionary = {"one", "two", "three"}
>
This creates a set. and NOT a di
I believe you're asking for the term "Cycle notation".
http://en.wikipedia.org/wiki/Cycle_notation
On Wed, Dec 4, 2013 at 7:56 PM, R. Alan Monroe wrote:
> Given two lists, before and after a sort:
> 0 1 2 3 4
> -
> before: 3 1 2 5 4
> after: 1 2 3 4 5
>
> Is the
On Wednesday 2013 December 04 19:56, R. Alan Monroe wrote:
> This seems like the kind of thing that probably exists, but there
> isn't a simple googlable term for searching it out conveniently.
Try "sorting algorithm".
--
Yonder nor sorghum stenches shut ladle gulls stopper torque wet
strainers
On Wed, Dec 4, 2013 at 8:13 PM, Jared Nielsen wrote:
> I want to create a dictionary, assign it keys, then iterate through a for
> loop and assign the dictionary values from a list. I'm trying this, but
> it's not working:
>
> dictionary = {"one", "two", "three"}
> list = [1,2,3]
>
>
Hi Jared,
'd
I want to create a dictionary, assign it keys, then iterate through a for
loop and assign the dictionary values from a list. I'm trying this, but
it's not working:
dictionary = {"one", "two", "three"}
list = [1,2,3]
for key in dictionary:
for value in list:
dictionary[key] = value
I
Given two lists, before and after a sort:
0 1 2 3 4
-
before: 3 1 2 5 4
after: 1 2 3 4 5
Is there a well-known algorithm that can give me the
list-of-transforms that got me from before to after?
e.g.:
first-to-zeroth,
zeroth-to-second,
second-to-first
fourth-to-third
On Wed, Dec 04, 2013 at 10:35:46AM +0100, Ismar Sehic wrote:
> hello, good people.
> i have a pretty urgent question.the situation is like this, i have
> following lists, as results of numerous psycopg2 queries, here are two
> examples :
Ismar, the following don't look like Python lists to me. It'
On 12/04/2013 10:35 AM, Ismar Sehic wrote:
[...]
Your presentation is a bit abscure (to me, at least): it is hard to help you.
Maybe you could explain better, and progressively:
* what is the purpose of your software, and its context
* what are your input data and what they mean, and whether
On Wed, 4 Dec 2013 10:35:46 +0100, Ismar Sehic
wrote:
so please, i need some pointers in how to get these lists related,
regarding i cannot use indexing, because i don't always have the
same
number of items in list.
First question is whether the data is assumed to be self consistent.
For
hello, good people.
i have a pretty urgent question.the situation is like this, i have
following lists, as results of numerous psycopg2 queries, here are two
examples :
for one hotel, id 3628 :
3628
[36L, 317L] - room type id
['DBP', 'DS5'] - room names
[Decimal('10.00'), Decimal('17.00'), Dec
Alan Gauld btinternet.com> writes:
>
> On 04/12/13 10:22, Wolfgang Maier wrote:
>
> >
> > # instead of senateInfo[lastName] = state,
> > # which builds a simple state dictionary
> > if lastName in senateInfo:
> > senateInfo[lastName].append((firstName, st
On Tue, Dec 03, 2013 at 09:51:12PM -0600, Byron Ruffin wrote:
> I realize the code snippet was bad. It was meant to be pseudo code. I was
> on my phone and far from pc. Anyway
>
> I tried this:
>
> already_seen = set()
> for name in last_names:
> if name in already_seen:
> print
On 04/12/13 03:51, Byron Ruffin wrote:
is doing this. Also, it seems to be referencing chars when variable
lastName is an item in a list.
Thats because you are looping over the name.
Loops work on any iterable or sequence.
A string is a sequence of chars so you can loop over a
string as easi
On 04/12/13 10:22, Wolfgang Maier wrote:
# instead of senateInfo[lastName] = state,
# which builds a simple state dictionary
if lastName in senateInfo:
senateInfo[lastName].append((firstName, state))
else:
senateInfo[lastName] = [(fi
Byron Ruffin g.austincc.edu> writes:
>
>
>
>
>
> I realize the code snippet was bad. It was meant to be pseudo code. I
was on my phone and far from pc. Anyway
> I tried this: already_seen = set()
> for name in last_names:
> if name in already_seen:
> print("Already seen",
I realize the code snippet was bad. It was meant to be pseudo code. I was
on my phone and far from pc. Anyway
I tried this:
already_seen = set()
for name in last_names:
if name in already_seen:
print("Already seen", name)
else:
already_seen.add(name)
I am not seeing
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