Hi.
And I thought I understood python pretty well. Until I got hit by this:
def f(x):
... print x
cb = [lambda :f(what) for what in 1234]
for c in cb:c()
4
4
4
4
And even this works
what = foo
for c in cb:c()
foo
foo
foo
foo
I expected the output to be 1 2 3 4. Now I understand the
Are you just trying to make a continuation?
On 5/3/06, Igor [EMAIL PROTECTED] wrote:
Hi.
And I thought I understood python pretty well. Until I got hit by this:
def f(x):
... print x
cb = [lambda :f(what) for what in 1234]
for c in cb:c()
4
4
4
4
And even this works
what =
On Wed, 2006-05-03 at 14:00 +0200, Igor wrote:
Hi.
And I thought I understood python pretty well. Until I got hit by this:
def f(x):
... print x
cb = [lambda :f(what) for what in 1234]
for c in cb:c()
4
4
4
4
cb = [(lambda x=what:f(x)) for what in 1234]
cb[0]()
1
A
Igor wrote:
Hi.
And I thought I understood python pretty well. Until I got hit by this:
def f(x):
... print x
cb = [lambda :f(what) for what in 1234]
for c in cb:c()
4
4
4
4
You haven't actually created a closure because you don't have any nested
scopes, you have global scope
On Wed, 3 May 2006, Igor wrote:
And I thought I understood python pretty well. Until I got hit by this:
def f(x):
... print x
cb = [lambda :f(what) for what in 1234]
for c in cb:c()
4
4
4
4
Hi Igor,
I think you're getting caught by something that isn't quite related to
closures
