I don't think I saw anyone point this out yet, but, using list as a
variable name is a bad idea, because it hides the list method.
x = list(abcdefg)
x
['a', 'b', 'c', 'd', 'e', 'f', 'g']
This works. You now have a variable named x that is a list.
list = list(hijklmnop)
list
['h', 'i', 'j',
Thank you all, very nice.
Steve Willoughby wrote:
Kent Johnson wrote:
Try
list.append({'id': 'name', 'link': ('YY','XX')[total 0]})
I'd caution against that, though. It's clever and cute, sure, but the
meaning of it is obfuscated enough to be unpythonic because [total 0]
as a
Kent Johnson wrote:
Try
list.append({'id': 'name', 'link': ('YY','XX')[total 0]})
I'd caution against that, though. It's clever and cute, sure, but the
meaning of it is obfuscated enough to be unpythonic because [total 0]
as a subscript doesn't mean anything unless you know you're
bob gailer wrote:
The terse version:
list.append({'id': 'name', 'link': ('XX','YY')[total 0]})
I think you have it backwards:
In [1]: total=0
In [2]: ('XX','YY')[total 0]
Out[2]: 'XX'
In [3]: total=1
In [4]: ('XX','YY')[total 0]
Out[4]: 'YY'
Try
list.append({'id': 'name', 'link':
Norman Khine wrote:
Hello,
Is there a better way to do this:
list = []
total = 0
if total 0:
... x = {'id': 'name', 'link': 'XX'}
... list.append(x)
... else:
... y = {'id': 'name', 'link': 'YY'}
... list.append(y)
...
I would like to change the key 'link'
Hello,
Is there a better way to do this:
list = []
total = 0
if total 0:
... x = {'id': 'name', 'link': 'XX'}
... list.append(x)
... else:
... y = {'id': 'name', 'link': 'YY'}
... list.append(y)
...
I would like to change the key 'link' value depending on the value of
