Is there a less clunky way to do this?
[code]
def new_pass():
series = ['`', '1', '2', '3', '4', '5', '6', '7', '8', '9', '0', '-',
'=', \
'~', '!', '@', '#', '$', '%', '^', '&', '*', '(', ')', '_',
'+', \
'q', 'w', 'e', 'r', 't', 'y', 'u', 'i', 'o', 'p', '[', ']',
'
On Wed, May 25, 2011 at 6:25 PM, Wolf Halton wrote:
> Is there a less clunky way to do this?
> [code]
> def new_pass():
> series = ['`', '1', '2', '3', '4', '5', '6', '7', '8', '9', '0', '-',
> '=', \
> '~', '!', '@', '#', '$', '%', '^', '&', '*', '(', ')', '_',
> '+', \
>
On Wed, 25 May 2011, 19:25:59 CEST, Wolf Halton wrote:
> [code]
> def new_pass():
> series = ['`', '1', '2', '3', '4', '5', '6', '7', '8', '9', '0', '-',
> '=', \
> '~', '!', '@', '#', '$', '%', '^', '&', '*', '(',
>')', '_',
> '+', \
>
Hello,
: Is there a less clunky way to do this?
Yes. There are probably many ways to do this, and this is just
something I cooked up at a moment's notice in reply to your
question, and probably could be significantly improved upon.
: def new_pass():
Your function takes no arguments. Mayb
On 5/25/11, Wolf Halton wrote:
> Is there a less clunky way to do this?
> [code]
> def new_pass():
> series = ['`', '1', '2', '3', '4', '5', '6', '7', '8', '9', '0', '-',
> '=', \
> '~', '!', '@', '#', '$', '%', '^', '&', '*', '(', ')', '_',
> '+', \
> 'q', 'w', 'e'
"Wolf Halton" wrote
Is there a less clunky way to do this?
def new_pass():
series = ['`', '1', '2', '3', '4', '5', '6', '7', '8', '9', '0',
'-',
'=', \
'~', '!', '@', '#', '$', '%', '^', '&', '*', '(', ')',
'_',
'+', \
'q', 'w', 'e', 'r', 't', 'y', 'u', 'i',
On 25/05/11 19:54, Modulok wrote:
Depending on what your passwords are going to be protecting, be aware that the
default generator in the random module is:
"...completely unsuitable for cryptographic purposes."
If he's just planning on making a few passwords I think the period of
2**19937-1 of
Now I see. I am going to go woodshed this. Thanks y'all for all the cool
ideas!
Wolf
On May 25, 2011 4:05 PM, "Adam Bark" wrote:
> On 25/05/11 19:54, Modulok wrote:
>> Depending on what your passwords are going to be protecting, be aware
that the
>> default generator in the random module is:
>>
On Wed, May 25, 2011 at 11:25 PM, Wolf Halton wrote:
> Is there a less clunky way to do this?
> [code]
> def new_pass():
> series = ['`', '1', '2', '3', '4', '5', '6', '7', '8', '9', '0', '-',
> '=', \
> '~', '!', '@', '#', '$', '%', '^', '&', '*', '(', ')', '_',
> '+', \
>
I have a 0.2 version
[code]
def new_pass(p):
valchars = string.ascii_letters + string.digits + string.punctuation
series = list(valchars)
pp = int(raw_input("Enter the length you want your password to be:[%i] "
% (p)) or p)
# length of password chosen or default length
On 05/26/2011 02:45 PM, Wolf Halton wrote:
Now I am looking at how to make it have an admin function to set the
valid characters, and have a way to output the password into main()
Simple, just learn to use the 'return' statement:
[code]
def new_pass(p):
pp = int(raw_input("Enter the len
On Thu, 26 May 2011 05:45:30 am Alan Gauld wrote:
[...]
> using
> the choice() function from the whrandom module.
>
> passwd = [whrandom.choice(series) for n in range(p)]
whrandom was deleted in Python 2.5! I'm not sure when it was formally
deprecated, but the recommended way of getting random n
"Steven D'Aprano" wrote
whrandom was deleted in Python 2.5!
Well, I'm using 2.5 but I confess I didn't try it,
I looked up my O'Reilly Python standard Library book
because I already had it to hand. It obviously predates 2.5! :-)
Alan G.
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