On Sun, 3 Aug 2008, CNiall wrote:
0.2
0.20001
0.33
0.33002
As you can see, the last two decimals are very slightly inaccurate.
However, it appears that when n in 1/n is a power of two, the decimal
does not get 'thrown off'. How might I make Python recognise
I am very new to Python (I started learning it just yesterday), but I
have encountered a problem.
I want to make a simple script that calculates the n-th root of a given
number (e.g. 4th root of 625--obviously five, but it's just an example
:P), and because there is no nth-root function in
CNiall wrote:
I want to make a simple script that calculates the n-th root of a given
number (e.g. 4th root of 625--obviously five, but it's just an example
:P), and because there is no nth-root function in Python I will do this
with something like x**(1/n).
Side note: of course there are
On Sun, Aug 3, 2008 at 10:04 AM, CNiall [EMAIL PROTECTED] wrote:
I want to make a simple script that calculates the n-th root of a given
number (e.g. 4th root of 625--obviously five, but it's just an example :P),
and because there is no nth-root function in Python I will do this with
something