Alan,
I am getting a syntax error when I print the following:
input = raw_input(Insert a number: )
try:
print float(input) * 12
except: TypeError, ValueError:
print False
The try is coming up as red. Any idea why?
On Fri, Nov 21, 2014 at 12:23 AM, Alan Gauld alan.ga...@btinternet.com
This one worked! Thank you very much! :D
On Fri, Nov 21, 2014 at 3:14 AM, Adam Jensen han...@riseup.net wrote:
On Thu, 20 Nov 2014 21:20:27 +
Stephanie Morrow svmor...@gmail.com wrote:
Hi there,
I have been posed with the following challenge:
Create a script that will ask for a
On 21/11/14 13:19, Stephanie Morrow wrote:
try:
print float(input) * 12
except: TypeError, ValueError:
print False
The try is coming up as red. Any idea why?
Sorry, I left the colon in after the else.
I think that's what's confusing it...
It should read:
except TypeError,
Alan Gauld wrote:
But that's considered bad practice, it's better to put the
valid errors only in the except line like this:
try:
print float(input)*12
except TypeError, ValueError:
print False
Careful, you need parens around the tuple of errors, otherwise this catches
only
-Original Message-
From: Tutor [mailto:tutor-bounces+hanzer=riseup@python.org] On
Behalf Of Alan Gauld
Sent: Thursday, November 20, 2014 7:24 PM
But that's considered bad practice, it's better to put the valid errors
only in
the except line like this:
try:
print
Hi there,
I have been posed with the following challenge:
Create a script that will ask for a number. Check if their input is a
legitimate number. If it is, multiply it by 12 and print out the result.
I was able to do this with the following code:
input = raw_input(Insert a number: )
if
I have been posed with the following challenge:
Create a script that will ask for a number. Check if their input is a
legitimate number. If it is, multiply it by 12 and print out the result.
I was able to do this with the following code:
input = raw_input(Insert a number: )
if
On Thu, Nov 20, 2014 at 3:05 PM, Stephanie Morrow svmor...@gmail.com wrote:
What else could I do in that testing portion that would allow for a decimal
point? In order for a decimal to be True, it would have to accept both the
digits and the decimal point.
Let's tackle a problem that's
What else could I do in that testing portion that would allow for a decimal
point? In order for a decimal to be True, it would have to accept both the
digits and the decimal point.
On Thu, Nov 20, 2014 at 10:36 PM, Danny Yoo d...@hashcollision.org wrote:
I have been posed with the following
On 20/11/14 21:20, Stephanie Morrow wrote:
input = raw_input(Insert a number: )
if input.isdigit():
print int(input) * 12
else:
print False
/However/, a colleague of mine pointed out that a decimal will return as
False. As such, we have tried numerous methods to allow it to divide
#!/usr/bin/env python3.4
good = False
s = input('Enter a number: ')
a = s.split('.')
n = len(a)
if n = 2:
for y in a:
if y.isdigit():
good = True
else:
good = False
exit
else:
good = False
if good:
num = float(s)
print(num * 12)
On Thu, 20 Nov 2014 21:20:27 +
Stephanie Morrow svmor...@gmail.com wrote:
Hi there,
I have been posed with the following challenge:
Create a script that will ask for a number. Check if their input is a
legitimate number. If it is, multiply it by 12 and print out the result.
I was
My response is interleaved with yours, below.
On Thu, Nov 20, 2014 at 09:20:27PM +, Stephanie Morrow wrote:
Hi there,
I have been posed with the following challenge:
Create a script that will ask for a number. Check if their input is a
legitimate number. If it is, multiply it by 12
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