Try again: I'm using the LIKE operator to match a pattern against a string using this SELECT statement:
for row in con.execute("SELECT <column> FROM <table> WHERE <string> LIKE '%q%' limit 25"): .. where <column>, <table>, <string> are placeholders! With q="dog" as a test example, I've tried '$q%', '%q%', '%q' and 'q%' and none of them return what I expect ie. all strings with the characters "dog" in them. Cheers! Dinesh ----- Original Message ----- From: Dinesh B Vadhia To: tutor@python.org Sent: Thursday, April 10, 2008 3:24 PM Subject: SQLite LIKE question I'm reading a text file into an in-memory pysqlite table. When I do a SELECT on the table, I get a 'u' in front of each returned row eg. > (u'QB VII',) > (u'Quackser Fortune Has a Cousin in the Bronx',) I've checked the data being INSERT'ed into the table and it has no 'u'. The second problem is that I'm using the LIKE operator to match a pattern against a string but am getting garbage results. For example, looking for the characters q='dog' in each string the SELECT statement is as follows: for row in con.execute("SELECT <column> FROM <table> WHERE <string> LIKE '%q%' limit 25"): print row This doesn't work and I've tried other combinations without luck! Any thoughts on the correct syntax for the LIKE? Dinesh
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