0, 9, 19, 29, 39, is not every 10th index
If you want to output every 10th. index try:
a100 = list(range(0,100,10))
for a in a100:
print(a)
-----Original Message-----
From: Gabriele Brambilla <gb.gabrielebrambi...@gmail.com>
To: python tutor <tutor@python.org>
Sent: Mon, 17 Feb 2014 16:06
Subject: [Tutor] for: how to skip items
Hi,
I'm wondering how I can (if I can) make a for loop in which I don't use all the
elements.
for example
a100 = list(range(100))
for a in a100:
print(a)
it print out to me all the numbers from 0 to 99
But if I want to display only the numbers 0, 9, 19, 29, 39, ...(one every 10
elements) how can I do it WITHOUT defining a new list (my real case is not so
simple) and WITHOUT building a list of indexes?
thank you
Gabriele
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