> well, I would have said "apply(zip, (l1, l2, l3, ...))" but apply has
> been deprecated in 2.3.
Hi Sean,
Sorry for straying away from the original poster's question, but do you
know why apply() is being deprecated? This is new to me! ... ok, I see
some discussion on it:
http://mail.python.
Shidai Liu wrote:
On Mon, 21 Mar 2005 22:51:31 -0800, Sean Perry <[EMAIL PROTECTED]> wrote:
arg_list = []
# fill up arg_list
zipped = zip(*arg_list)
I met a similar question.
what if one has L = [[1,2],[3,4]], K = [100, 200]
What do you want to do with these lists?
How to 'zip' a List like [[1,2,10
On Mon, 21 Mar 2005 22:51:31 -0800, Sean Perry <[EMAIL PROTECTED]> wrote:
> Tony Cappellini wrote:
>
> well, I would have said "apply(zip, (l1, l2, l3, ...))" but apply has
> been deprecated in 2.3.
>
> So how about this?
>
> arg_list = []
> # fill up arg_list
> zipped = zip(*arg_list)
>
I met
Tony Cappellini wrote:
I have a program which currently passes 6 lists as arguments to zip(),
but this could easily change to a larger number of arguments.
Would someone suggest a way to pass a variable number of lists to zip() ?
well, I would have said "apply(zip, (l1, l2, l3, ...))" but apply
I have a program which currently passes 6 lists as arguments to zip(), but
this could easily change to a larger number of arguments.
Would someone suggest a way to pass a variable number of lists to zip() ?
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