> 5100- 3
> 5100 foo 1
> 5200 - 1
> 5200 foo 1
> I want to count the frequency of the second column of data that I can
> access.
It's kind of the long way around, but putting it into a sql database
and doing a groupby query might work.
Alan
> Hooray, right?! However, my real problem is dealing with another
> dimension of data. So suppose I can access the following data:
>
> "5100", "foo"
> "5100", "-"
> "5100", "-"
> "5100", "-"
> "5200", "foo"
> "5200", -
Hint: Dictionaries can be keyed by tuples too.
>( 5100, -) : 3
Does tha
On 8/11/06, Terry Peppers <[EMAIL PROTECTED]> wrote:
> I'm really blocked right now, and I don't want to post this to the
> main Python list since I think the answer is probably right in front
> of my face. I'm clearly just too close to see it.
>
> "5100", "foo"
> "5100", "-"
> "5100", "-"
> "5100"
I'm really blocked right now, and I don't want to post this to the
main Python list since I think the answer is probably right in front
of my face. I'm clearly just too close to see it.
I'm able to do frequency counts of items in a list by doing the following:
>>> list = ["5100", "5100", "5100",
