hi I got it right.
z=[]
for x in range(1000):
if divmod(x,3)[1]==0:z.append(x)
if divmod(x,5)[1]==0:z.append(x)
sum(set(z))
233168
I am sorry if this is outside the perimeter of this list.
___
Tutor maillist - Tutor@python.org
On Sun, Jan 4, 2009 at 14:18, prasad rao prasadarao...@gmail.com wrote:
z=[]
for x in range(1000):
if divmod(x,3)[1]==0:z.append(x)
if divmod(x,5)[1]==0:z.append(x)
sum(set(z))
233168
This can be done in one line of python.
sum([x for x in range(1000) if x %3 == 0 or x % 5 == 0])
233168
prasad rao prasadarao...@gmail.com wrote
http://svn.python.org/view/python/trunk/Objects/listobject.c?rev=67498view=markup
Kent ! This is grek and latin to me.From the presence of header
files it
looks C++.But headerfiles are not between '' and '' .
Its C rather than C++.
The in
On Sat, Dec 27, 2008 at 3:42 AM, Alan Gauld alan.ga...@btinternet.comwrote:
Its C rather than C++.
The in include statements are a variation on the which can also be
used.
The differences are subtle and have to do with the search path I think. But
its
been so long since I did serious
Thanks for help.
http://svn.python.org/view/python/trunk/Objects/listobject.c?rev=67498view=markup
Kent ! This is grek and latin to me.From the presence of header files it
looks C++.But headerfiles are not between '' and '' .
But why are you trying to sort in this fashion?
Alan Gauld!
