On Nov 1, 2007, at 3:04 PM, Alan Gauld wrote:
> Where does the if/else syntax come from? It doesn't
> seem to work on my Python 2.4. Is it a new feature in 2.5?
Yes, it's a new feature in 2.5.
- Jeff Younker - [EMAIL PROTECTED]
___
Tutor maillist -
"Eric Brunson" <[EMAIL PROTECTED]> wrote
>last = Popen( command,
> stdin=last.stdout if last else None,
> stdout=PIPE )
Where does the if/else syntax come from? It doesn't
seem to work on my Python 2.4. Is it a new feature in 2.5?
Alan G.
___
Eric and Eric :-)
Thanks both for the suggestions! I learned from each!
I believe the small function will work for me. Its simple since I don't
have to track each pipe I open with a variable. I had no idea I could do
that nifty if/then for the stdin, that makes it so easy. :-)
Thanks again!
J
"jay" <[EMAIL PROTECTED]> wrote
> I'm a little stumped as to how to handle the variables. If I have
> an
> arbitrary number of PIPES, how do I declare my variables (p1, p2,
> p3,
> etc...) ahead of time in the function??
How about passing a list of pipes?
Then you can access them as pipes[0]
jay wrote:
> Hello,
>
> If I have multiple Popen calls I need to make, how can I turn these
> into a function?
Since you're only interested in the output of the last command on the
pipeline, I don't see a reason to keep track of them all. I'd do
something like this:
def pipeline( *commandlist
Hi Jay...
jay wrote:
...
> I would be sending an arbitrary number of PIPES with each function call.
>
> I'm a little stumped as to how to handle the variables. If I have an
> arbitrary number of PIPES, how do I declare my variables (p1, p2, p3,
> etc...) ahead of time in the function??
>
> Tha
Hello,
If I have multiple Popen calls I need to make, how can I turn these into a
function?
from subprocess import Popen, PIPE
p1 = Popen(['ls', '-l', '-a', '/etc'],stdout=PIPE)
p2 = Popen(['grep', 'hosts'], stdin=p1.stdout, stdout=PIPE)
p3 = Popen(['awk', '{print $1}'], stdin=p2.stdout, stdout=
