I am fine tuning list comprehensions (at least my understandng
thereof), and I'm not near a Python interpreter at the moment, so
I
was wondering if someone could tell me if I did OK -
def approachB(files):
isHTML = [filename if filename.endswith('.htm') or\
isHTML = [filename if filename.endswith('.htm') or\
filename.endswith(.html') for filename in files]
return isHTML
No, it should be...
Well spotted, but...
isHTML = [filename for filename in files if
filename.endswith('.htm') or\
filename.endswith('.html') for filename in
Hello,
I am fine tuning list comprehensions (at least my understandng
thereof), and I'm not near a Python interpreter at the moment, so I
was wondering if someone could tell me if I did OK -
def approachA(files):
isHTML = []
for filename in files:
if
Hello,
I am fine tuning list comprehensions (at least my understandng
thereof), and I'm not near a Python interpreter at the moment, so I
was wondering if someone could tell me if I did OK -
def approachA(files):
isHTML = []
for filename in files:
if filename.endswith('.htm') or
def approachB(files):
isHTML = [filename if filename.endswith('.htm') or\
filename.endswith(.html') for filename in files]
return isHTML
No, it should be...
isHTML = [filename for filename in files if
filename.endswith('.htm') or\
filename.endswith('.html') for filename in
Kent Johnson wrote:
Liam Clarke wrote:
Hello,
I am fine tuning list comprehensions (at least my understandng
thereof), and I'm not near a Python interpreter at the moment, so I
was wondering if someone could tell me if I did OK -
def approachA(files):
isHTML = []
for filename in files: