On Sun, Jun 06, 2010 at 07:52:43PM +1000, Lie Ryan wrote:
> >>> re.sub('(one) (two)', r'\g<0> - \1 \2',s)
>
> the \g is equivalent to \number but is intended to ambiguate
> cases like "\g<2>0" vs. "\20". It happens that \g<0> refers to the
> entire group.
Thanks a lot. It works as you say.
With
On 06/06/10 19:36, Payal wrote:
> On Sun, Jun 06, 2010 at 06:26:18PM +1000, Steven D'Aprano wrote:
>> Two things. Firstly, the Python regex engine numbers backreferences from
>> 1, not 0, so you need \1 and not \0.
>
> Thank for the mail, but i am still not getting it. e.g.
>
> In first sub I e
On Sun, Jun 06, 2010 at 06:26:18PM +1000, Steven D'Aprano wrote:
> Two things. Firstly, the Python regex engine numbers backreferences from
> 1, not 0, so you need \1 and not \0.
Thank for the mail, but i am still not getting it. e.g.
>>> import re
>>> s = 'one two'
>>> re.sub('(one) (two)', r'
On Sun, 6 Jun 2010 05:32:26 pm Payal wrote:
> Hi,
> A newbie re query.
>
> >>> import re
> >>> s='one'
> >>> re.sub('(one)','only \\0',s)
>
> 'only \x00'
>
> >>> re.sub('(one)','only \0',s)
>
> 'only \x00'
>
> I expected the output to be 'only one' with \0 behaving like "&" in
> sed. What is wrong
Hi,
A newbie re query.
>>> import re
>>> s='one'
>>> re.sub('(one)','only \\0',s)
'only \x00'
>>> re.sub('(one)','only \0',s)
'only \x00'
I expected the output to be 'only one' with \0 behaving like "&" in sed.
What is wrong with my syntax?
With warm regards,
-Payal
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