Michael Langford wrote:
> A neater way to do it looks like:
>
> dic2 = {}
> countOfVars=40
> for line in file('foo.dat'):
> tokens = line.split()
> dval = tokens[0]
> ls = []
> for i in range(1,countOfVars+1):
> ls.append(float(tokens[i]))
> dic2[dval]=tuple(ls)
> p
Bryan Fodness wrote:
> it doesn't fix the problem, now it says there is a syntax error on the
> equal sign.
Please, post your code and the exact error message and traceback! Don't
make us guess what you are doing!
My guess is you forgot the closing ) but I have no way to know for sure.
Kent
>
Using the attached foo.dat and no linebreaks, what you're doing works
perfectly:
dic2 = {}
for line in file('foo.dat'):
d, fs1, fs2, fs3, fs4, fs5, fs6, fs7, fs8, fs9, fs10, fs11, fs12, fs13,
fs14, fs15, fs16, fs17, fs18, fs19, fs20, fs21, fs22, fs23, fs24, fs25,
fs26, fs27, fs28, fs29, fs30, f
it works well if it is on the same line, but I would like to wrap it for
readability
On 10/21/07, Bryan Fodness <[EMAIL PROTECTED]> wrote:
>
> it doesn't fix the problem, now it says there is a syntax error on the
> equal sign.
>
> On 10/21/07, Alan Gauld <[EMAIL PROTECTED]> wrote:
> >
> >
> > "Br
it doesn't fix the problem, now it says there is a syntax error on the equal
sign.
On 10/21/07, Alan Gauld <[EMAIL PROTECTED]> wrote:
>
>
> "Bryan Fodness" <[EMAIL PROTECTED]> wrote in
>
> >d, fs1, fs2, fs3, fs4, fs5, fs6, fs7, fs8, fs9, fs10,
> >fs11, fs12, fs13, fs14, fs15, fs16, fs17, f
"Bryan Fodness" <[EMAIL PROTECTED]> wrote in
>d, fs1, fs2, fs3, fs4, fs5, fs6, fs7, fs8, fs9, fs10,
>fs11, fs12, fs13, fs14, fs15, fs16, fs17, fs18, fs19,
>fs20, fs21, fs22, fs23, fs24, fs25, fs26, fs27, fs28,
>fs29, fs30, fs31, fs32, fs33, fs34, fs35, fs36, fs37,
>fs38, fs39
Here is my code.
dic2 = {}
for line in file('21Ex6MV_tmr.dat'):
d, fs1, fs2, fs3, fs4, fs5, fs6, fs7, fs8, fs9, fs10,
fs11, fs12, fs13, fs14, fs15, fs16, fs17, fs18, fs19,
fs20, fs21, fs22, fs23, fs24, fs25, fs26, fs27, fs28,
fs29, fs30, fs31, fs32, fs33, fs34, fs35, fs36, fs37,
If the ease of use is the only answer then the size of the file should not
matter ideally. btw, how large is the file ? is it in MBs or GBs ? For
performance reasons, typically you should not have any problems using either
dictionary, array or list for file size of few KBs.
Like Kent said, if you
Bryan Fodness wrote:
> The data file is larger than shown, and I was wondering if it would be
> better to populate an array or create a dictionary. Which would be
> easier?
>
A dictionary is an array with an index, if you need an index into your
data, use a dictionary, if not use an array.
>
The data file is larger than shown, and I was wondering if it would be
better to populate an array or create a dictionary. Which would be easier?
On 10/19/07, Kent Johnson <[EMAIL PROTECTED]> wrote:
>
> Bryan Fodness wrote:
> > I have a data file that I would like to extract data from:
> >
> > F
Bryan Fodness wrote:
> I have a data file that I would like to extract data from:
>
> FS 1 2 3 4 5
> 1.5 1.000 1.000 1.000 1.000 1.000
> 2.0 0.985 0.994 0.997 0.996 0.996
> 2.5 0.967 0.976 0.981 0.981 0.982
> 3.0 0.949 0.958 0.965 0.966 0.967
> 3.
I have a data file that I would like to extract data from:
FS 1 2 3 4 5
1.5 1.000 1.000 1.000 1.000 1.000
2.0 0.985 0.994 0.997 0.996 0.996
2.5 0.967 0.976 0.981 0.981 0.982
3.0 0.949 0.958 0.965 0.966 0.967
3.5 0.925 0.937 0.945 0.948 0.
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