Thankyou. got it.
On Sat, Apr 15, 2017 at 5:44 AM, Steven D'Aprano
wrote:
> On Fri, Apr 14, 2017 at 11:59:25PM +0530, shubham goyal wrote:
>
> > sorted(ls)
> > sorted(ls1)
>
> Here you sort ls and throw the result away, then you do the same to ls1.
>
> sorted() makes a copy of the list and s
On Fri, Apr 14, 2017 at 11:59:25PM +0530, shubham goyal wrote:
> sorted(ls)
> sorted(ls1)
Here you sort ls and throw the result away, then you do the same to ls1.
sorted() makes a copy of the list and sorts it. You need to write:
ls = sorted(ls)
ls1 = sorted(ls1)
but even better would be t
Change your code to
def front_x(words):
# +++your code here+++
ls=[]
ls1=[]
for str in words:
if str[0]=='x':
ls.append(str)
else:
ls1.append(str);
print ls
print ls1
ls = sorted(ls)
ls1 = sorted(ls1)
ls.extend(ls1)
return ls
regards,
Sarma.
O
On 14/04/17 19:29, shubham goyal wrote:
> sorted function is not working when i am trying to sort the list of strings
> but list.sort() is working. can you please help me understand.
sort() sorts the list "in place". That is it sorts itself.
sorted() returns a sorted copy of the list. It does not
Dear mentors,
sorted function is not working when i am trying to sort the list of strings
but list.sort() is working. can you please help me understand.In this
question i was trying to sort the list but first sorting the letter
starting from x and taking them first.
def front_x(words):
# +++your
