Hi Steven,
On 2 January 2012 06:28, Steven D'Aprano st...@pearwood.info wrote:
That only applies to decimal values which can be represented using a fixed
number of decimal places. So 1/5 is fine, and is 0.2 exactly, but 1/3 is
not, since it would require an infinite number of decimal places.
(You accidentally forgot to include the list when you replied. The
easiest way (for most people) to avoid that is to use Reply-all)
On 01/02/2012 01:00 AM, Sarma Tangirala wrote:
On 2 Jan 2012 08:56, Dave Angeld...@davea.name wrote:
Easiest answer is to use integers. Scale everything up
Hi again,
On 2 January 2012 06:28, Steven D'Aprano st...@pearwood.info wrote:
Another answer is to use Decimal class, which CAN represent decimal values
exactly.
That only applies to decimal values which can be represented using a fixed
number of decimal places. So 1/5 is fine, and is 0.2
Hello,
Can some please explain this to me?
My while loop should continue while owed is greater than or equal to d
first time the function is called
the loop exits as expected
False: 0.00 = 0.01
the next time it does not
False: 0.01 = 0.01
Below is the snippet of code, and the out
On 01/01/2012 09:48 PM, brian arb wrote:
Hello,
Can some please explain this to me?
My while loop should continue while owed is greater than or equal to d
first time the function is called
the loop exits as expected
False: 0.00= 0.01
the next time it does not
False: 0.01= 0.01
On Mon, Jan 2, 2012 at 3:48 AM, brian arb brianjames...@gmail.com wrote:
Hello,
Can some please explain this to me?
My while loop should continue while owed is greater than or equal to d
first time the function is called
the loop exits as expected
False: 0.00 = 0.01
the next time
Dave Angel wrote:
Easiest answer is to use integers. Scale everything up by a factor of
100, and you won't need floats at all. Just convert when printing (and
even then you may get into trouble).
Another answer is to use Decimal class, which CAN represent decimal
values exactly.
That
