Thanks for clearing this up for me.
On Tue, 2008-12-02 at 13:25 -0800, Steve Willoughby wrote:
> On Tue, Dec 02, 2008 at 01:08:09PM -0800, Jeremiah Jester wrote:
> > Hello,
> >
> > I'm trying to gather a list of files and md5 hash them to do a
> checksum.
> > I've created a function for each dict
On Tue, Dec 02, 2008 at 01:08:09PM -0800, Jeremiah Jester wrote:
> Hello,
>
> I'm trying to gather a list of files and md5 hash them to do a checksum.
> I've created a function for each dictionary. However, when i print out
> the dictionary I don't get all the items. Any ideas?
Yep. Don't use os
Thank you all, this is exactly what I was trying to do and the syntax is
beautiful... :-)
--
Pablo Englebienne
"Progress is made by lazy men looking for easier ways to do things." - Robert
A. Heinlein
Kent Johnson wrote:
On Thu, Nov 13, 2008 at 10:01 AM, A.T.Hofkamp <[EMAIL PROTECTED]> wro
Kent Johnson wrote:
On Thu, Nov 13, 2008 at 10:01 AM, A.T.Hofkamp <[EMAIL PROTECTED]> wrote:
d3 = dict(( (rv, dict.fromkeys(c)) for rv in r ))
You don't need the double parentheses, this works just as well:
d3 = dict( (rv, dict.fromkeys(c)) for rv in r )
A generator expression just has to be
On Thu, Nov 13, 2008 at 10:01 AM, A.T.Hofkamp <[EMAIL PROTECTED]> wrote:
d3 = dict(( (rv, dict.fromkeys(c)) for rv in r ))
You don't need the double parentheses, this works just as well:
d3 = dict( (rv, dict.fromkeys(c)) for rv in r )
A generator expression just has to be in parentheses, it'
On Thu, Nov 13, 2008 at 8:11 AM, Pablo Englebienne
<[EMAIL PROTECTED]> wrote:
> Hi, I'm trying to work with a dictionary of dictionaries and I'm having
> trouble accessing a specific element of it:
>
> $ python
> Python 2.6 (trunk:66714:66715M, Oct 1 2008, 18:36:04)
> [GCC 4.0.1 (Apple Computer, I
Pablo Englebienne wrote:
Hi, I'm trying to work with a dictionary of dictionaries and I'm having
trouble accessing a specific element of it:
$ python
Python 2.6 (trunk:66714:66715M, Oct 1 2008, 18:36:04)
[GCC 4.0.1 (Apple Computer, Inc. build 5370)] on darwin
Type "help", "copyright", "credits
On Fri, Jun 13, 2008 at 10:23 AM, [EMAIL PROTECTED]
<[EMAIL PROTECTED]> wrote:
> Hi,
> Following Alan's post, what I was trying to do is to understand how I
> can return the sub-item within the same space, if it makes sense ;)
Um, no, not to me. Is your question about creating a structure or acces
Hello,
Thank you for the replies. I wanted to hold the data in memory,
because the number of records do not warrant the need to have to
maintain an additional relational database. Plus I wanted to understand
how to build this using classes as this will perhaps give me the bridge
I require to mo
"Marilyn Davis" <[EMAIL PROTECTED]> wrote
When see nested builtin data structures, I always think it's time to
think
of making a few classes instead.
It could be, especially if you are about to write a bunch of
functions to access those structures. But equally if the
structures accurately re
On Fri, June 13, 2008 7:23 am, [EMAIL PROTECTED] wrote:
> Hi,
> Following Alan's post, what I was trying to do is to understand how I
> can return the sub-item within the same space, if it makes sense ;)
>
> For example, in my 3 one-to-many lists, I want to generate this list:
When see nested bui
Hi,
Following Alan's post, what I was trying to do is to understand how I
can return the sub-item within the same space, if it makes sense ;)
For example, in my 3 one-to-many lists, I want to generate this list:
[{'id': ,
'category': [{'id': ,
'sub-c
On Thu, Jun 12, 2008 at 7:56 AM, [EMAIL PROTECTED]
<[EMAIL PROTECTED]> wrote:
> Hi,
> I would like to understand how to generate dictionaries based on other
> dictionaries. For example, I have a 3 tables in ym SQL database -
> Groups, Categories and Sub-categories with a one-to-many relations
> bet
<[EMAIL PROTECTED]> wrote
I am presuming that each of these tables is one of my
dictionaries?!?!
What I don't understand is how to write this SQL statement in python
code:
SELECT id, category from Categories WHERE group_id = "1";
SQL is designed(and optimised) for doing complex data querie
bob gailer wrote:
> if key not in keywords:
>keywords[key] = []
> keywords[key].append(value)
This can be written more succinctly as
keywords.setdefault(key, []).append(value)
or in Python 2.5:
from collections import defaultdict
keywords = defaultdict(list)
...
keywords[key
Dinesh B Vadhia wrote:
> Hello! I'm creating a dictionary called keywords that has multiple
> entries each with a variable list of values eg.
>
> keywords[1] = [1, 4, 6, 3]
> keywords[2] = [67,2]
> keywords[3] = [2, 8, 5, 66, 3, 23]
> etc.
>
> The keys and respective values (both are integers
"Dinesh B Vadhia" <[EMAIL PROTECTED]> wrote
keywords[1] = [1, 4, 6, 3]
keywords[2] = [67,2]
keywords[3] = [2, 8, 5, 66, 3, 23]
etc.
The keys and respective values (both are integers) are read
in from a file. For each key, the value is append'ed until
the next key. Here is the code.
..
Thanks so much I changed to the following and this worked:
def HolderDistributionqty(dictionary):
from collections import defaultdict
count=defaultdict(int)
for item in dictionary.values():
count[len(item)]+=1
for k,v in sorted(count.items()):
fdist=k
qty=v
GTXY20 wrote:
>
> Thanks again I have worked that issue out.
>
> However I have the following function and it is throwing this error:
>
> FEXpython_v2.py", line 32, in UnitHolderDistributionqty
> count[item]+=1
> KeyError: 3
>
> This is the function:
>
> def Distributionqty(dictionary
Thanks again I have worked that issue out.
However I have the following function and it is throwing this error:
FEXpython_v2.py", line 32, in UnitHolderDistributionqty
count[item]+=1
KeyError: 3
This is the function:
def Distributionqty(dictionary):
holder=list()
held=list()
dis
GTXY20 wrote:
> Hello,
>
> Any way to display the count of the values in a dictionary where the
> values are stored as a list? here is my dictionary:
>
> {'1': ['a', 'b', 'c'], '3': ['a', 'b', 'c'], '2': ['a', 'b', 'c'], '4':
> ['a', 'c']}
>
> I would like to display count as follows and I would
GTXY20 wrote:
>
> This works perfectly.
>
> However I will be dealing with an import of a very large dictionary - if
> I call the commands at command line this seems to be very taxing on the
> CPU and memory and will take a long time.
>
> I was thinking of creating each as a fucntion whereb
This works perfectly.
However I will be dealing with an import of a very large dictionary - if I
call the commands at command line this seems to be very taxing on the CPU
and memory and will take a long time.
I was thinking of creating each as a fucntion whereby python would just to
write to a fi
GTXY20 wrote:
> Hello,
>
> Any way to display the count of the values in a dictionary where the
> values are stored as a list? here is my dictionary:
>
> {'1': ['a', 'b', 'c'], '3': ['a', 'b', 'c'], '2': ['a', 'b', 'c'], '4':
> ['a', 'c']}
>
> I would like to display count as follows and I wou
"GTXY20" <[EMAIL PROTECTED]> wrote
> Any way to display the count of the values in a dictionary where the
> values
> are stored as a list? here is my dictionary:
>
> {'1': ['a', 'b', 'c'], '3': ['a', 'b', 'c'], '2': ['a', 'b', 'c'],
> '4':
> ['a', 'c']}
>
> I would like to display count as foll
Tony Waddell wrote:
> I am wondering how look for a key in a dictionary, given a value.
>
> I have a dictionary similar to this:
> a = { 'a1':1, 'a2':2, 'a3':3, 'a4'.:4}
>
> If I have the value of 2, how would I look at the dictionary to turn
> that into 'a2'.
You have to search the values. This
> for key in sorted(result.keys): a sorted list of keys
Oops, that should of course be:
for key in sorted(result.keys() ):
Alan G.
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Chris, You seem to be going through several hoops that
you don't need here. Let the data structures do the work
of storage and extract the data you want in its various
pieces. You are getting the entire data set in a string
then trying to pick out the bits you want, that defeats
the purpose of havi
Chris Hallman wrote:
>
> I need some suggestions on how to work with a dictionary. I've got a
> program that builds a dictionary. I need to be able to manipulate the
> different keys and data so that I can write the output to a file AND
> utilize the smtplib to send the data in an email. I had p
Title: Message
Chris,
This looks similar to what I do for my job. I
would be happy to help you, if I
can.
My first question is, how would you like the output
to look? Can you manually create a model of the email text you want to
send?
My second question is, can you create the
email
Chris Hallman wrote:
>
> I need some suggestions on how to work with a dictionary. I've got a
> program that builds a dictionary. I need to be able to manipulate the
> different keys and data so that I can write the output to a file AND
> utilize the smtplib to send the data in an email. I had p
> For example, I have a dictionary:
> dict1 = { 0x2018:u'k', 0x2019:u'd'}
>
> I assign:
> n = 0x2018
> print dict1[n]
>
> Then:
> KeyError: '0x2018'
The error is complaining that you are using a string as a key.
Are you sure you aren't assigning
n = '0x2018'
Alan G
Author of the learn to progr
kakada wrote:
> I assign:
> n = 0x2018
> print dict1[n]
>
> Then:
> KeyError: '0x2018'
>
Notice the error menstions a *string*. You probably mistyped it, not in
the email, but in your actual program.
Hugo
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http
It also works for me now:)
First i tried it with Konsole in Kate and it's not working.
It sometimes happen with assignment statement:
i += 1 (not working)
i+= 1(working)
but later on I tested it again and both are working.
Thanks for your help, though.
da
Jason Massey wrote:
> Works for
On Tue, 2006-04-11 at 22:37 -0500, Jason Massey wrote:
> Works for me:
>
> >>> dict1 = { 0x2018:u'k', 0x2019:u'd'}
> >>> n = 0x2018
> >>> print dict1[n]
> k
> >>>
>
> On 4/11/06, kakada <[EMAIL PROTECTED]> wrote:
> Hello all,
>
> For example, I have a dictionary:
>
Works for me:>>> dict1 = { 0x2018:u'k', 0x2019:u'd'}>>> n = 0x2018>>> print dict1[n]k>>> On 4/11/06,
kakada <[EMAIL PROTECTED]> wrote:
Hello all,For example, I have a dictionary:dict1 = { 0x2018:u'k', 0x2019:u'd'}I assign:n = 0x2018print dict1[n]Then:KeyError: '0x2018'But I can call directly:print
> I should have known. sheesh python is so kewl. I keep forgetting most
> times,
> it will do stuff directly and you don't have to assign..
Whether thats 'kewl' depends on your viewpoint.
>From a pure computing point of view returning a value is more consistent
and correct in a functional program
ahh man,
I should have known. sheesh python is so kewl. I keep forgetting most times,
it will do stuff directly and you don't have to assign..
Thanks
Python Newbie
On Friday 11 November 2005 02:59 pm, DS wrote:
> You almost have it. Do this instead.
>
> d = {'first':[]}
> d['first'].appe
You almost have it. Do this instead.
d = {'first':[]}
d['first'].append("string")
Append acts on the list, so assignment is unnecessary.
ds
Eric Walker wrote:
>All,
>I have a dictionary say:
>d = {'first':[]}
>I am going through another list and depending on whats going on,
>I want to add to t
On 11/11/05, Eric Walker <[EMAIL PROTECTED]> wrote:
> All,
> I have a dictionary say:
> d = {'first':[]}
> I am going through another list and depending on whats going on,
> I want to add to the empty list. I have tried the following to noavail.
>
> d['first'] = d['first'].append("string")
>
> I wo
> Oh, about four years ago :-) in Python 2.2
>
> You really should read the "What's New in Python x.x" docs ;)
:-)
Hmm, I usually skim them but pick up most of my info from this
list because I rarely upgrade to the latest version right away
- I only upgraded my XP box. to 2.4 a few weeks ago..
> I used to want that syntax when I started, now I stick to for x in
> y.keys()
I knew you could do
for item in dictionary:
instead of
for item in dictionary.keys():
But I didn't realise it worked for a single item test too
if item in dictionary
instead of
if dictionary.has_key(item):
Whi
On Behalf Of Alan
Gauld
Sent: Monday, 7 November 2005 8:51 a.m.
To: Kent Johnson
Cc: tutor@python.org
Subject: Re: [Tutor] Dictionary Error: 'dict' object has noattribute
'_contains_'
> But you normally shouldn't call this directly, you should write
> "test&quo
Alan Gauld wrote:
>> But you normally shouldn't call this directly, you should write
>> "test" in menu_specials
>
>
> Now howzabout that! Yet another new trick learnt.
> When did 'in' start working with dictionaries?
Oh, about four years ago :-) in Python 2.2
You really should read the "What's
> But you normally shouldn't call this directly, you should write
> "test" in menu_specials
Now howzabout that! Yet another new trick learnt.
When did 'in' start working with dictionaries?
Alan G.
___
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> Hi! I'm on the version 2.4, going through Beginning Python (Wrox), and
> I'm getting the above error. I'm trying to do this:
>
> menu_specials._contains_("test")
>
> Any ideas on what I'm doing wrong? Thanks!
It looks like you may be reading the wrong book!
Why they would suggest you ever exec
Trent Rigsbee wrote:
> Hi! I'm on the version 2.4, going through Beginning Python (Wrox), and I'm
> getting the above error. I'm trying to do this:
>
> menu_specials._contains_("test")
>
> Any ideas on what I'm doing wrong? Thanks!
The name of the method is __contains__ (note *double* leading
> A dictionary stores its values based on the keys. Internally Python
> sorts the keys to make the lookup meet performance expectations.
>
> You can not expect a dictionary to return keys in the other you added
> them. If you want that, store the items as tuples in a list.
Or you can sort the k
> > I typed:
> > landUse = {'res': 1, 'com': 2, 'ind': 3, "other" :[4,5,6,7]}
> > and when i checked landUse, I found it become:
> > {'ind': 3, 'res': 1, 'other': [4, 5, 6, 7], 'com': 2}
> > why the order is changed?
>
> the docs warn you about this.
Hi Shi,
By the way, here's a post from a lon
Shi Mu wrote:
> I typed:
> landUse = {'res': 1, 'com': 2, 'ind': 3, "other" :[4,5,6,7]}
> and when i checked landUse, I found it become:
> {'ind': 3, 'res': 1, 'other': [4, 5, 6, 7], 'com': 2}
> why the order is changed?
the docs warn you about this.
A dictionary stores its values based on the ke
Shi Mu <[EMAIL PROTECTED]> 2005-10-24 09:13:
> why the order is changed?
By definition a dictionary has no order.
jem
--
Jan Erik Moström, www.mostrom.pp.se
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you work with dictionary.
In dictionary you work with the key to get your value. You don't care about how python arrange the key.
your key here are: 'res', 'com', 'ind', and 'other'
when you want to get your value you just type:
landUse['res'] this you will get 1
landUse['ind'] this you will get 3
David Driver wrote:
> If I
> create a dictionary with the same keys, will it str the same way?
This behaviour is not guaranteed and I wouldn't depend on it. It can break if
any other operations have happened on the dict; for example
>>> d=dict(a=1,b=2,c=23)
>>> str(d)
"{'a': 1, 'c': 23, 'b': 2
Kent Johnson said unto the world upon 08/07/2005 21:09:
> Brian van den Broek wrote:
>
>>if you care about the possibility that there is no unique key with the
>>lowest value, I'd do:
>>
>> >>> def get_low_keys(a_dict):
>>... '''-> list of keys in a_dict with lowest value'''
>>... min_val = m
Brian van den Broek wrote:
> if you care about the possibility that there is no unique key with the
> lowest value, I'd do:
>
> >>> def get_low_keys(a_dict):
> ... '''-> list of keys in a_dict with lowest value'''
> ... min_val = min(a_dict.values())
> ... low_keys = []
> ... for k,v in
luke p wrote:
> just assume all the below code is correct.
> I am not having a problem with it, it is all for example only.
>
> I have a dictionary like this:
> alpha = {'a':0,'b':0, ... 'z':0}
> and the following code
> f = file("hamlet.txt","r")
> text = f.readlines()
> f.close()
> for line in t
luke p said unto the world upon 08/07/2005 19:40:
> just assume all the below code is correct.
> I am not having a problem with it, it is all for example only.
>
> I have a dictionary like this:
> alpha = {'a':0,'b':0, ... 'z':0}
> and the following code
> f = file("hamlet.txt","r")
> text = f.rea
Don Parris said unto the world upon 08/07/2005 20:09:
> On 7/8/05, luke p <[EMAIL PROTECTED]> wrote:
>>what I want to do is find out which value in my dictionary is lowest.
>>is there a dictionary function for this, like alpha.min() that will
>>return a key:value pair of the lowest? I cannot fi
On 7/8/05, luke p <[EMAIL PROTECTED]> wrote:
> just assume all the below code is correct.
> I am not having a problem with it, it is all for example only.
>
> I have a dictionary like this:
> alpha = {'a':0,'b':0, ... 'z':0}
> and the following code
> f = file("hamlet.txt","r")
> text = f.readline
On Thu, May 19, 2005 at 09:47:50PM +0100, Max Noel wrote:
>
>On May 19, 2005, at 20:49, William O'Higgins wrote:
>
>>I am trying to discover the syntax for call on a dictionary of
>>lists by
>>key and index.
>>
>>The data structure looks like this:
>>
>>dol = {'key1':['li1','li2','li3'],'key2':['
On May 19, 2005, at 20:49, William O'Higgins wrote:
> I am trying to discover the syntax for call on a dictionary of
> lists by
> key and index.
>
> The data structure looks like this:
>
> dol = {'key1':['li1','li2','li3'],'key2':['li1','li2','li3'],\
> 'key3':['li1'li2,'li3','']}
>
> The keys
Indeed, dictionaries don't have a .key attribute.
Instead, use:
# Get list of values for 'key1'
aList = dol[ 'key1' ]
This would return the list of values you have assigned to 'key1' in
the dictionary. Once you got that list, you can look in the list to
find out the index of 'lil1' and return i
Arrgh! How could I be so stupid! :)
Thanks for the help! I know many things about python, but I can't
believe that I didn't know that!
Thanx again!
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On May 5, 2005, at 16:37, Allen John Schmidt, Jr. wrote:
> Ok, I have had enough. I have looked all through the python docs and I
> cannot find it. How do you insert an entry into a dictionary?
>
The way you think it's done:
>>> a = {'foo': 1, 'bar': 2}
>>> a
{'foo': 1, 'bar': 2}
>>> a[
Allen John Schmidt, Jr. wrote:
> Ok, I have had enough. I have looked all through the python docs and I
> cannot find it. How do you insert an entry into a dictionary?
>
> Thanx!
>
>>> my_dict = {}
>>> my_dict['new_entry'] = ['simple', 'as', 1, 2, 3]
>>> my_dict
{'new_entry': ['simple', 'as'
Here's some quick examples:
>>> dictMe = {}
>>> dictMe['SomeKey'] = 'SomeValue'
>>> dictMe
{'SomeKey': 'SomeValue'}
>>> dictMe[1] = 100
>>> dictMe
{1: 100, 'SomeKey': 'SomeValue'}
>>> type(dictMe)
Section 5.5 of the Python tutorial covers dictionaries a little more in depth.
http://docs.python.o
> >if D.has_key(event.keysym):
> > str=D[event.keysym]
> >self.text.insert(END,str)
>
> You can remove the 'text.' thats only used if text
> were part of a class, which in this case it isn't.
Oops, that should say remove 'self.' not text.
Alan G.
___
11:51 PM
Subject: Re: [Tutor] Dictionary blues...
My deepest and most sincere apologies - cooking dinner for the family and
posting questions do not mix, I keep making mistakes in the code I type.
Once again my apologies - here's the code as it is in my source:
import sys, os, unicodedat
;p':
str='t'
elif event.keysym=='t':
str='z'
put all the conversion values into a dictionary and make the function use
the key:value pairs from dictionary.
I hope I am making sense.
Igor
- Original Message -
From: "Alan Gauld" <[EMAIL
Igor,
> I posted the wrong code before. The code is:
Is this the actual code you have written? If so it is
so far from being working code that it suggests you
need to back up a little and work at the basics of
Python before trying to tackle Tkinter and GUIs.
I'll assume this really is your co
On Wed, 23 Mar 2005, Igor Riabtchuk wrote:
> I posted the wrong code before. The code is:
>
> from Tkinter import *
>
> D={a:"tom", b:"dick", c:"harry"}
>
> text.bind('', self.Conv)
>
> def Conv(self,event):
> if D.has_key(event.keysym):
> str=D[event.keysym]
> self.text.insert(END
Ah, see, I should convince my bosses that I need a Python interpreter.
Of course, then they'd ask what Python was, and why I was thinking
about it at work
Duh, I was just reading the docs, and I kept thinking that an
attribute was just a class variable.
Thanks, Kent, now I have all sorts of i
Liam Clarke wrote:
Hi,
just an expansion on Brian's query, is there a variant of getattr for
instance methods?
i.e. class DBRequest:
def __init__(self, fields, action):
self.get(fields)
def get(self, fields):
print fields
Instead of self.get in _init__, the value of
Hi,
just an expansion on Brian's query, is there a variant of getattr for
instance methods?
i.e. class DBRequest:
def __init__(self, fields, action):
self.get(fields)
def get(self, fields):
print fields
Instead of self.get in _init__, the value of action to call a
Jeff Shannon said unto the world upon 2005-02-16 16:09:
On Tue, 15 Feb 2005 23:48:31 -0500, Brian van den Broek
<[EMAIL PROTECTED]> wrote:
Yes, if you know that you will only have one header per line, then
it's reasonable to process them one line at a time. You could
alternatively have the TP_f
Kent Johnson said unto the world upon 2005-02-16 15:02:
Brian van den Broek wrote:
I had been thinking better to get everything working and then
refactor. Is that an unsound approach? My worry about refactoring now
is that I feel like I am rearranging deck-chairs when I should be
worried about
On Tue, 15 Feb 2005 23:48:31 -0500, Brian van den Broek
<[EMAIL PROTECTED]> wrote:
> Jeff Shannon said unto the world upon 2005-02-15 21:20:
> > On Tue, 15 Feb 2005 17:19:37 -0500, Brian van den Broek
> > <[EMAIL PROTECTED]> wrote:
> >
> > For starters, I've made metadata a class attribute rather t
Brian van den Broek wrote:
As for the code smell thing, I have a follow-up question. I now get the
point of the type-based conditional being a smell for classes. (I get it
due to a previous thread that an over-enthusiastic inbox purge prevents
me from citing with certainty, but I think it was Bi
Brian van den Broek said unto the world upon 2005-02-16 14:04:
Kent Johnson said unto the world upon 2005-02-16 05:58:
if 'text' == self.document_type:
self.do_text_stuff()
if 'RTF' == self.document_type:
self.do_RTF_stuff()
Conditionals on a 'type' flag are a code smell that suggests using
Kent Johnson said unto the world upon 2005-02-16 05:58:
Brian van den Broek wrote:
Also, I know the general security concerns about things like exec.
They make me nervous in using it, even though I am (as yet) the sole
user. Am I right in thinking that the constrained way I am using it
here pro
Kent Johnson wrote:
Another way to do this is to use dispatch methods. If you have extra
processing to do for each tag, this might be a good way to go.
I'm going to assume that your data lines have the form 'tag=data'. Then
your Node class might have methods that look like this:
class Node:
.
Brian van den Broek wrote:
My Node class defines a _parse method which separates out the node
header, and sends those lines to a _parse_metadata method. This is where
the elif chain occurs -- each line of the metadata starts with a tag
like "dt=" and I need to recognize each tag and set the appr
Jeff Shannon said unto the world upon 2005-02-15 21:20:
On Tue, 15 Feb 2005 17:19:37 -0500, Brian van den Broek
<[EMAIL PROTECTED]> wrote:
My Node class defines a _parse method which separates out the node
header, and sends those lines to a _parse_metadata method. This is
where the elif chain occu
On Tue, 15 Feb 2005 17:19:37 -0500, Brian van den Broek
<[EMAIL PROTECTED]> wrote:
> My Node class defines a _parse method which separates out the node
> header, and sends those lines to a _parse_metadata method. This is
> where the elif chain occurs -- each line of the metadata starts with a
> ta
Liam Clarke said unto the world upon 2005-02-15 18:08:
Hi Brian, why not take it the next step and
for key in metadata_dict:
if data.startswith(key):
exec('''self.%s = """%s"""''' %(metadata_dict[key],
data[len(key):]))
# tripl
Hi Brian, why not take it the next step and
> for key in metadata_dict:
> if data.startswith(key):
> exec('''self.%s = """%s"""''' %(metadata_dict[key],
> data[len(key):]))
> # triple quotes as there may be quotes in meta
Brian van den Broek wrote:
[snip text]
class A:
def __init__(self):
self.something = None
self.something_else = None
self.still_another_thing = None
def update(self, data):
for key in metadata_dict:
if data.startswith(key):
exec('''self.%s = ""
> If I want to put a dictionary in a dictionary, does the syntax
> for assigning and getting at the stuff in the inner dictionary
> look something like this: outer_dictionary[inner_dictionary][key] =
'value'
Yes.
Sometimes it's easier with Python to just try it at the >>> prompt
rather than ask t
jhomme wrote:
Hi,
If I want to put a dictionary in a dictionary, does the syntax for assigning
and getting at the
stuff in the inner dictionary look something like this:
outer_dictionary[inner_dictionary][key] = 'value' > ?
If inner_dictionary is the key to outer_dictionary, then that is right. Fo
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