Hi there. I make a Twitter app. for android.
I sent an update using HttpURLConnection. but it isn't working. my code is... ================================================================ String uri = "http://twitter.com/statuses/update.xml";; HttpURLConnection connection = (HttpURLConnection) new URL (uri).openConnection(); connection.setRequestMethod("POST"); connection.setDoOutput(true); connection.setRequestProperty("Content-Type", "application/x-www-form- urlencoded"); connection.setRequestProperty("Authorization", "Basic " + Base64.encode (name + ":" + password)); String data = URLEncoder.encode("status") + "=" + URLEncoder.encode ("TEST!"); connection.setRequestProperty("User-Agent", "myTwitterApp"); connection.setRequestProperty("Content-Length", "" + data.getBytes ().length); OutputStream oStream = connection.getOutputStream(); oStream.write(data.getBytes("UTF-8")); oStream.flush(); oStream.close(); int responsecode = connection.getResponseCode(); switch (responsecode) { case 200: break; case 403: case 404: Log.e("conn X", responsecode + " : " + connection.getResponseMessage ()); return null; default: break; } ================================================================== when I make this code, I expect just one HTTP Post packet. but there are two packet. first packet is POST /statuses/update.xml HTTP/1.1 ~~ content-length: 41 second packet is status=The+First+update+from+myapp When I call OutputStream oStream = connection.getOutputStream(); the first packet is sent. and then, when I call int responsecode = connection.getResponseCode(); the second packet is sent. so, responsecode is 403 Client must provide a 'status' parameter with a value. please help me.
