> -Original Message-
> I'm trying to avoid having to write a subroutine to,
> basically, always round up the result of a division between a
> multi-value field and a single-value one, in an I-descriptor
> (UV 10.1).
>
> My MV field is named CONS, my single value one is names
> UNITS,
Morgan
Sent: Monday, March 26, 2007 11:22 AM
To: u2-users@listserver.u2ug.org
Subject: RE: [U2] UniVerse I-descriptor Help
> -Original Message-
> I'm trying to avoid having to write a subroutine to,
> basically, always round up the result of a division between a
> multi-
i feel it should be INT(CONS/REUSE(UNITS)+ 0.5)
Thanks,
Somanshu Baghel
- Original Message
From: Norman Morgan <[EMAIL PROTECTED]>
To: u2-users@listserver.u2ug.org
Sent: Monday, March 26, 2007 11:52:25 PM
Subject: RE: [U2] UniVerse I-descriptor Help
> -Original Message--
> i feel it should be INT(CONS/REUSE(UNITS)+ 0.5)
You are correct, of course. I rounded in the wrong place.
===
Norman Morgan <> [EMAIL PROTECTED] <> http://www.brake.com
===
The Queue
isnt there an iconvs & oconvs SUBR routine ?
I dont have manuals or pdf's available at the moment
Rich
IT-Laure Hansen wrote:
Hello,
I'm trying to avoid having to write a subroutine to, basically, always
round up the result of a division between a multi-value field and a
single-value one, i
ehalf Of Norman Morgan
Sent: Monday, March 26, 2007 3:34 PM
To: u2-users@listserver.u2ug.org
Subject: RE: [U2] UniVerse I-descriptor Help
> i feel it should be INT(CONS/REUSE(UNITS)+ 0.5)
You are correct, of course. I rounded in the wrong place.
You are also going to need the INT function that operates on multi-values,
!INTS.
__
From: Moderator <[EMAIL PROTECTED]>
Reply-To: u2-users@listserver.u2ug.org
To: u2-users@listserver.u2ug.org
Subject:
Behalf Of Janke, Mark
Sent: Monday, March 26, 2007 1:28 PM
To: u2-users@listserver.u2ug.org
Subject: RE: [U2] UniVerse I-descriptor Help
Actually, I think you would need to use the REUSE function on the 0.5
also; otherwise the 0.5 will be added to only the first value in the
intermediate result of
