I had, after 25 minutes of heavy thought, worked out that it actually was
relevant! That's scary!
Bob
On Dec 12, 2010, at 5:03 PM, Colin Holgate wrote:
>
>
> For anyone slightly confused by that, I was telling a colleague about changes
> in Google Docs for iPad, and pasted the reply into t
For anyone slightly confused by that, I was telling a colleague about changes
in Google Docs for iPad, and pasted the reply into th ewrong window!
Hope some of you were intrigued anyway.
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P
On Dec 12, 2010, at 3:20 PM, Charles Szasz wrote:
> For example, comparing -3.5 with 2.23. How do you do this?
This may sum it up:
While Google recently updated its mobile version of Google Docs to support
editing on smartphones, it acknowledged the feature was somewhat limited. The
new vers
Colin,
Thanks a lot! I had forgotten about the absolute function. I now have to figure
out how to do comparisons of this sort so that if a negative number is bigger
than a positive value that it is reported as a weakness (such as -3.5 compared
with a value of 2.23). And if a positive number is
Hi Charles,
It's been a long time for me, but if I remember well you want either the first
differences or the standard deviation.
function mean theNumbers
return sum(theNumbers)/number of items of theNumbers
end mean
function firstDifferences theNumbers
put mean(theNumbers) into myMean
re
On Dec 12, 2010, at 3:20 PM, Charles Szasz wrote:
> For example, comparing -3.5 with 2.23. How do you do this?
You can use abs to get the positive absolute value, and compare those:
put abs(-3.5)>abs(2.23)
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I am computing an average of a series of numbers and then comparing each number
with the average, which yields a deviation. Of course, there are instances
where a negative deviation will occur when it is below the average.
Here is my problem. I need to be able to compare a negative number with
